Question

我在DB中有一个包含数据列的字段，但是在一个连续的XML字符串中。我想从XML中提取数据，并返回普通列。在这个单一字段中可能有多行数据。

以下是此字段中2个真实的数据示例

示例1：

<DocumentElement>    
    <AuditTrailDetail>      
        <TableName>order_header_total</TableName>      
        <RowID>837</RowID>      
        <AuditType>Edit</AuditType>      
        <FieldName>oht_foreign_net</FieldName>     
        <ValueFrom>65.1600</ValueFrom>      
        <ValueTo>115.1600</ValueTo>      
        <EntityName />     
        <DisplayName />      
        <Identifier />    
    </AuditTrailDetail>   
    <AuditTrailDetail>     
        <TableName>order_line_item</TableName>     
        <RowID>2442</RowID>      
        <AuditType>Edit</AuditType>     
        <FieldName>oli_qty_required</FieldName>      
        <ValueFrom>1.0000</ValueFrom>     
        <ValueTo>2.0000</ValueTo>      
        <EntityName />      
        <DisplayName />      
        <Identifier>61 - test</Identifier>    
    </AuditTrailDetail>  
</DocumentElement>

示例2：

<DocumentElement>   
    <AuditTrailDetail>      
        <TableName>order_line_item</TableName>      
        <RowID>2446</RowID>      
        <AuditType>Edit</AuditType>     
        <FieldName>oli_description</FieldName>      
        <ValueFrom>2 Ply Tissue Masks</ValueFrom>     
        <ValueTo>2 Ply Tissue Masksdd</ValueTo>      
        <EntityName />     
        <DisplayName />      
        <Identifier>D/D170 - 2 Ply Tissue Masksdd</Identifier>   
    </AuditTrailDetail>  
</DocumentElement>

对于示例1，我想返回2行，如下所示：

example1

对于例2，有一行，我想它如下：

Example2

表格中的字段为：

owat_id
owat_audit_type
owat_record_id
owat_record_type
owat_datetime
owat_ud_id
owat_details

XML数据在owat_details。

之内

假设表名为Audit_Trail。

如何在SQL查询中直接执行此操作？

Answer 1

感谢Johnie Karr

我使用XQuery工作了。

我必须进行2次查询并将它们组合在一起，以便将一个字段中的2个单独元素作为单独的行。我确定有一个更清洁的解决方案，但这很有效。

非常感谢：）

SELECT 
AuditTrail.owat_record_type,
AuditTrail.owat_audit_type,
AuditTrail.owat_datetime as 'Audit Date',
user_detail.ud_username as 'User',
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/TableName)[1]','varchar(50)') AS TableName,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/RowID)[1]','varchar(50)') AS RowID,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/FieldName)[1]','varchar(50)') AS FieldName,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/ValueFrom)[1]','varchar(50)') AS ValueFrom,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/ValueTo)[1]','varchar(50)') AS ValueTo,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/Identifier)[1]','varchar(50)') AS Identifier
FROM 

    (select
    orderwise_audit_trail.owat_id,
    orderwise_audit_trail.owat_audit_type,
    orderwise_audit_trail.owat_record_id,
    orderwise_audit_trail.owat_record_type,
    orderwise_audit_trail.owat_datetime,
    orderwise_audit_trail.owat_ud_id,
    convert(xml, orderwise_audit_trail.owat_details) as owat_details
    from
    orderwise_audit_trail) as AuditTrail

left join user_detail on user_detail.ud_id = AuditTrail.owat_ud_id  

Where AuditTrail.owat_details is not NULL
and (AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/TableName)[1]','varchar(50)')) is not null

UNION ALL

SELECT 
AuditTrail.owat_record_type,
AuditTrail.owat_audit_type,
AuditTrail.owat_datetime as 'Audit Date',
user_detail.ud_username as 'User',
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/TableName)[2]','varchar(50)') AS TableName,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/RowID)[2]','varchar(50)') AS RowID,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/FieldName)[2]','varchar(50)') AS FieldName,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/ValueFrom)[2]','varchar(50)') AS ValueFrom,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/ValueTo)[2]','varchar(50)') AS ValueTo,
AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/Identifier)[2]','varchar(50)') AS Identifier

FROM 

    (select
    orderwise_audit_trail.owat_id,
    orderwise_audit_trail.owat_audit_type,
    orderwise_audit_trail.owat_record_id,
    orderwise_audit_trail.owat_record_type,
    orderwise_audit_trail.owat_datetime,
    orderwise_audit_trail.owat_ud_id,
    convert(xml, orderwise_audit_trail.owat_details) as owat_details
    from
    orderwise_audit_trail) as AuditTrail

left join user_detail on user_detail.ud_id = AuditTrail.owat_ud_id  

Where AuditTrail.owat_details is not NULL
and (AuditTrail.owat_details.value('(/DocumentElement/AuditTrailDetail/TableName)[2]','varchar(50)')) is not null

order by 1, 2, 3, 4

XML数据到行选择

1 个答案: