我是编程的新手,可能这将是一个愚蠢的问题,但现在是:
这是我的班级主席:
public class Board {
public static final int COLOR_WHITE = 1;
public static final int COLOR_BLACK = 2;
PlayingPiece[][] board;
private boolean isFirstMove;
private int color;
public Board() {
this.setBoard(new PlayingPiece[8][8]);
this.isFirstMove = true;
this.initializePieces();
}
// Initialize the chess pieces
public void initializePieces() {
for (int i = 0; i < 8; i++) {
board[1][i] = new Pawn(1, i, COLOR_WHITE);
}
for (int i = 0; i < 8; i++) {
board[6][i] = new Pawn(6, i, COLOR_BLACK);
}
board[0][0] = new Rook(0, 0, COLOR_WHITE);
board[0][7] = new Rook(0, 7, COLOR_WHITE);
board[7][0] = new Rook(7, 0, COLOR_BLACK);
board[7][7] = new Rook(7, 7, COLOR_BLACK);
board[0][1] = new Knight(0, 1, COLOR_WHITE);
board[0][6] = new Knight(0, 6, COLOR_WHITE);
board[7][1] = new Knight(7, 1, COLOR_BLACK);
board[7][6] = new Knight(7, 6, COLOR_BLACK);
board[0][2] = new Officer(0, 2, COLOR_WHITE);
board[0][5] = new Officer(0, 5, COLOR_WHITE);
board[7][2] = new Officer(7, 2, COLOR_BLACK);
board[7][5] = new Officer(7, 5, COLOR_BLACK);
board[0][3] = new Queen(3, 0, COLOR_WHITE);
board[0][4] = new King(4, 0, COLOR_WHITE);
board[7][3] = new Queen(7, 3, COLOR_BLACK);
board[7][4] = new King(7, 4, COLOR_BLACK);
this.printBoard();
}
public boolean play(int color, int fromX, int fromY, int toX, int toY) {
boolean isTrue = false;
// Check if this is the first turn and only white can move
if (isFirstMove && color == COLOR_WHITE) {
isTrue = true;
} else if (isFirstMove && color == COLOR_BLACK) {
return false;
}
// check if player plays 2 times in a raw and if you move the piece from
// current possition
if (color == this.color || (toX == fromX && toY == fromY)) {
return false;
}
isTrue = true;
if (isTrue == true) {
this.isFirstMove = false;
// Check if player plays with his own color
if (((board[fromX][fromY]).getColor() != color)) {
return false;
}
// Check the isLegal movement of every chess piece
if ((board[fromX][fromY]).move(toX, toY)) {
board[toX][toY] = board[fromX][fromY];
board[fromX][fromY] = null;
}
this.printBoard();
}
return isTrue;
}
public PlayingPiece[][] getBoard() {
return board;
}
public void setBoard(PlayingPiece[][] board) {
this.board = board;
}
我想得到这个的价值:
board[toX][toY];
好了之后,这是我的另一个国际象棋课程:
public class PlayingPiece {
public static final int COLOR_WHITE = 1;
public static final int COLOR_BLACK = 2;
public static final char BLACK_PAWN = '\u265F';
public static final char BLACK_ROOK = '\u265C';
public static final char BLACK_KNIGHT = '\u265E';
public static final char BLACK_BISHOP = '\u265D';
public static final char BLACK_QUEEN = '\u265B';
public static final char BLACK_KING = '\u265A';
public static final char WHITE_PAWN = '\u2659';
public static final char WHITE_ROOK = '\u2656';
public static final char WHITE_KNIGHT = '\u2658';
public static final char WHITE_BISHOP = '\u2657';
public static final char WHITE_QUEEN = '\u2655';
public static final char WHITE_KING = '\u2654';
public static final char NO_PIECE = ' ';
private int x, y;
private boolean isAlive;
private int color;
private char symbol;
protected PlayingPiece (int newX, int newY, int newColor) {
this.setX(newX);
this.setY(newY);
this.color = newColor;
this.isAlive = true;
}
protected PlayingPiece(int newX, int newY) {
this.setX(newX);
this.setY(newY);
}
protected PlayingPiece() {
}
public int getX() {
return x;
}
public void setY(int y) {
this.y = y;
}
public int getY() {
return y;
}
public void setX(int x) {
this.x = x;
}
protected boolean moveIsLegal (int newX, int newY) {
boolean isLegal = false;
if ((0 <= newX && newX <= 7) && (0 <= newY && newY <= 7)){
isLegal = true;
}
return isLegal;
}
public boolean move (int newX, int newY) {
if (moveIsLegal(newX, newY)) {
setX(newX);
setY(newY);
return true;
}
return false;
}
public int getColor() {
return color;
}
public boolean isAlive() {
return isAlive;
}
public void setAlive(boolean isAlive) {
this.isAlive = isAlive;
}
public char getSymbol() {
return symbol;
}
public void setSymbol(char symbol) {
this.symbol = symbol;
}
}
现在这是Pawn类扩展了PlayingPieces:
public class Pawn extends PlayingPiece {
private boolean hasBeenMoved;
protected Pawn(int newX, int newY, int color) {
super(newX, newY, color);
this.hasBeenMoved = false;
if (color == COLOR_BLACK) {
this.setSymbol(BLACK_PAWN);
} else {
this.setSymbol(WHITE_PAWN);
}
}
@Override
public boolean move(int newX, int newY) {
if (super.move(newX, newY)) {
this.hasBeenMoved = true;
return true;
}
return false;
}
@Override
protected boolean moveIsLegal(int newX, int newY) {
boolean isLegal = false;
int newPositionX = newX - this.getX();
if (super.moveIsLegal(newX, newY)) {
if ((hasBeenMoved == false)
&& (((Math.abs(newPositionX) <= 2) && getY() == newY))) {
isLegal = true;
} else if ((hasBeenMoved == true)
&& (((Math.abs(newPositionX) <= 1) && getY() == newY)) && isValidTrace(newX, newY)) {
isLegal = true;
}
}
return isLegal;
}
public boolean isValidTrace(int newX, int newY) {
PlayingPiece[][] array = new PlayingPiece[8][8];
if (array[newX][newY].equals(new PlayingPiece())) {
return false;
}
return true;
}
}
现在在这个方法中isValidTrace()
我希望从课堂上获得board[toX][toY]
的价值,我怎么能在没有延伸的情况下这样做?
答案 0 :(得分:1)
另一种解决方案(假设您不需要多个Board实例)正在使电路板静止。
public static PlayingPiece[][] board;
然后您可以使用Board.board
答案 1 :(得分:0)
我不知道我是否理解你的问题但是......
如果您有2个A和B类而不是继承,则可以使用聚合。例如,您想要使用A类中对象B的某些方法:
class A {
private B b;
}
然后在A类的内部方法中使用b.nameOfTheMethod()
答案 2 :(得分:0)
您可以创建一个方法来返回数组,并在您想要数据的类中调用它。
public PlayingPiece getBoard()
{
return board;
}