这是一个创建点云的示例,然后我想要将其与曲面相匹配。当我尝试将meshgrid数组传递给插入数据的函数时,问题就出现了:
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
# Create some point cloud data:
c = 1
a = 3
b = 4
slice = {}
t = np.linspace(0,2*np.pi,50)
for s in np.linspace(1,9,10):
c = 5*s
r = (-s**2+10.0*s)/10.0
X = r*np.cos(t)
Y = r*np.sin(t)
Z = c*(Y**2/b**2 - X**2/a**2) + c
slice[str(int(s))] = np.vstack([X,Y,Z])
# Visualize it:
fig = plt.figure()
ax = fig.gca(projection = '3d')
for k,v in slice.iteritems():
print type(v)
print np.shape(v)
X = v[0,:]
Y = v[1,:]
Z = v[2,:]
ax.scatter(X,Y,Z)
plt.show()
看起来像这样:
我现在需要根据这些点创建表面网格。在这种情况下,表面有多种解释,因为我只有一个点云而不是一个函数z = f(x,y),但在这种情况下,正确的表面应该是创建一个空心的#34;扭曲的圆柱体# 34 ;.我想过像这样攻击这个问题:
# stack all points from each slice into one vector for each coordinate:
Xs = []
Ys = []
Zs = []
for k,v in slice.iteritems():
#ax.plot_surface(X,Y,Z)
X = v[0,:]
Y = v[1,:]
Z = v[2,:]
Xs = np.hstack((Xs,X))
Ys = np.hstack((Ys,Y))
Zs = np.hstack((Zs,Z))
XX, YY = np.meshgrid(Xs,Ys)
from scipy import interpolate
f = interpolate.interp2d(Xs,Ys,Zs, kind = 'cubic')
ZZ = f(XX,YY)
然后我可以使用
进行绘图fig = plt.figure()
ax = fig.gca(projection = '3d')
ax.plot_surface(XX, YY, ZZ)
plt.show()
然而,插值函数似乎不接受数组作为输入,因此此方法可能无效。任何人都可以提出如何正确地做到这一点的建议吗?
实际上,数据显然无法表示为函数,因为它不是一对一的。