Question

我正在尝试从PostgreSQL编写一个可在Oracle中运行的转换。我的问题是我正在努力寻找一个替代Postgres @>（包含）运算符的Oracle SQL语句。

Postgres中的查询如下所示：

CASE    
    WHEN descriptivegroup @> '{Building}' AND descriptiveterm IS NULL THEN 'Building Fill'
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm = '{"Multi Surface"}' THEN 'Multi Surface Fill'

等，这意味着'Building'或'General Surface'（在上面的示例中）应该包含在名为descriptivegroup的数组中。

我一直在浏览Stackoverflow和其他网站，我认为我在Oracle中为@>找到的最接近的等价物是“成员”，如下例所示：

How to check if an array contains a particular string?

然而，我正在努力研究如何将这样的陈述写入CASE＆gt;什么类型的声明，所以我会非常感激地从这个社区获得任何帮助或建议！

非常感谢。

PS正如所承诺的，这是Postgres查询的截断版本。这不是一切，因为它太大了：

CREATE TABLE osmm.topo_area_style AS SELECT
a.*,
CASE    
    WHEN descriptivegroup @> '{Building}' AND descriptiveterm IS NULL THEN 'Building 

Fill'
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm = '{"Multi 

Surface"}' THEN 'Multi Surface Fill'
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm IS NULL AND make 

= 'Natural' THEN 'Natural Fill'
    WHEN descriptivegroup @> '{"Road Or Track"}' AND descriptiveterm IS NULL AND make = 

'Manmade' THEN 'Road Or Track Fill'
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm IS NULL AND make 

= 'Manmade' OR make = 'Unknown' THEN 'Manmade Fill'
    WHEN descriptivegroup @> '{Roadside}' AND make = 'Natural' THEN 'Roadside Natural 

Fill'
    ELSE 'Unclassified' 
    END AS style_description,
CASE
    WHEN descriptivegroup @> '{Building}' AND descriptiveterm IS NULL THEN 1
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm = '{"Multi 

Surface"}' THEN 2
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm IS NULL AND make 

= 'Natural' THEN 3
    WHEN descriptivegroup @> '{"Road Or Track"}' AND descriptiveterm IS NULL AND make = 

'Manmade' THEN 4
    WHEN descriptivegroup @> '{"General Surface"}' AND descriptiveterm IS NULL AND make 

= 'Manmade' OR make = 'Unknown' THEN 5
    WHEN descriptivegroup @> '{Roadside}' AND make = 'Natural' THEN 6
    WHEN descriptivegroup @> '{Roadside}' AND make = 'Manmade' OR descriptivegroup @> 

'{Roadside}' AND make = 'Unknown' THEN 7
    ELSE 99 
    END AS style_code
FROM osmm.topographicarea as a;

我无法访问此SQL编写的表，但是您可以看到正在创建的表是现有表的直接副本，但是此代码添加了另外2列，然后从描述性组中填充descriptiveterm。

Oracle相当于Postgres'@＆gt; （包含）函数

0 个答案: