Question

我尝试使用以下代码显示数据库中的记录：

<?php 

include("carconnect.php");

$sqlGet ="SELECT * FROM cars";
$sqlData = mysqli_query($connect , $sqlGet) or die ("Error retrieving data!");

while ($row = mysqli_fetch_array($sqlData , MYSQLI_ASSOC)) {
echo $row['car'];
}

?>

基本上我在网页上的所有内容都是错误检索数据信息..

更新：语音标记不应该抱歉。

Answer 1

"之前的$sqlData = "mysqli_query中有mysqli_query。请删除它或尝试以下代码。

尝试

include("carconnect.php");

$sqlGet ="SELECT * FROM cars";
$sqlData = mysqli_query($connect , $sqlGet) or die ("Error retrieving data!");

while ($row = mysqli_fetch_array($sqlData , MYSQLI_ASSOC)) {
echo $row['car'];
}

Answer 2

使用另一种简单易用的方法：

<?php 
$host='hostname';
$dbuser='dbusername';
$dbpass='pass';
$dbname='databasename';
$conn= new mysqli('$hostname','$dbuser','$dbpass','$dbname');

$sqlGet ="SELECT * FROM cars";
$result=$conn->query('$sqlget');

while($sqlData= $result->fetch_assoc())
{
   echo $row['car'];
}
?>

Answer 3

试试这个：

include("carconnect.php");
$sqlGet ="SELECT * FROM cars";
$sqlData = mysqli_query($connect , $sqlGet) or die ("Error retrieving data!");
$row = mysqli_fetch_array($sqlData , MYSQLI_NUM);
foreach ($row as $value) {
    echo $value;
}

PHP试图从MySQL数据库显示数据

3 个答案: