如何在jax-rs jersey web服务中获得JSON作为响应？

Question

 package com.webservice.rest.jaxb;

    import javax.xml.bind.annotation.XmlRootElement;

    @XmlRootElement(name="employee")
    public class Employee {
    String name;
    String id;
    String location;
    float salary;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getId() {
        return id;
    }
    public void setId(String id) {
        this.id = id;
    }
    public String getLocation() {
        return location;
    }
    public void setLocation(String location) {
        this.location = location;
    }
    public float getSalary() {
        return salary;
    }
    public void setSalary(float salary) {
        this.salary = salary;
    }
      @Override
      public String toString() {
        return "Name [Id=" + id + ", Location=" + location
            + ", Salary=" + salary  + "]";
      }
}

这是我的employeewebservice

  package com.webservice.rest.jaxb;

    import javax.ws.rs.GET;
    import javax.ws.rs.Path;
    import javax.ws.rs.Produces;
    import javax.ws.rs.core.MediaType;

    @Path("/employee")
    public class EmployeeResource {


              @GET
              @Path("/getjson")
              @Produces({MediaType.APPLICATION_JSON})

              public Employee getJSon() {
                  Employee emp = new Employee();
                    emp.setName("Ankesh");
                    emp.setId("2096");
                    emp.setLocation("Pune_Kolkata");
                    emp.setSalary(2097868);
                    return emp;
              }

    }

下面是Web .xml

   <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"   
    xmlns="http://java.sun.com/xml/ns/javaee"   
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee   
    http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"   
    id="WebApp_ID" version="3.0"> 
     <display-name>JaxbWithrs</display-name>
     <servlet>
        <servlet-name>Jersey REST Service</servlet-name>
        <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
         <!-- Register resources and providers under com.vogella.jersey.first package. -->
        <init-param>
            <param-name>jersey.config.server.provider.packages</param-name>
            <param-value>com.webservice.rest.jaxb</param-value>
        </init-param>
        <init-param>
            <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
            <param-value>true</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
      </servlet>
      <servlet-mapping>
        <servlet-name>Jersey REST Service</servlet-name>
        <url-pattern>/rest/*</url-pattern>
      </servlet-mapping>
    </web-app>

Iam得到以下例外

  

找不到媒体类型= application / json的MessageBodyWriter，   type = class com.webservice.rest.jaxb.Employee，genericType = class   com.webservice.rest.jaxb.Employee。

下面是我的lib目录的截图

如果我错过任何事情，请告诉我！