我刚开始学习MongoDB。 有人可以提供一些关于如何用mongodb实现这个例子的东西吗?
示例
# Here are my categories
> hmset category:1 name cinema ... more fields ...
> hmset category:2 name music ... more fields ...
> hmset category:3 name sports ... more fields ...
> hmset category:4 name nature ... more fields ...
# Here are my users
> hmset user:1 name Jack ... more fields ...
> hmset user:2 name John ... more fields ...
> hmset user:3 name Julia ... more fields ...
# Let's establish the many-to-many relationship
# Jack likes cinema and sports
# John likes music and nature
# Julia likes cinema, music and nature
# For each category, we keep a set of reference on the users
> sadd category:1:users 1 3
> sadd category:2:users 2 3
> sadd category:3:users 1
> sadd category:4:users 2 3
# For each user, we keep a set of reference on the categories
> sadd user:1:categories 1 3
> sadd user:2:categories 2 4
> sadd user:3:categories 1 2 4
答案 0 :(得分:0)
在MongoDB中,您可以选择预先加入数据,因此可以将文档放在:
user : "John",
categories : ["music", "nature"]
还可以选择放置引用(更像是RDBMS):
user : "John",
categories : [ ObjectId("1e222222222"),
ObjectId("2e333333") ]
这基本上取决于您的数据访问模式。所以,如果您基本上只是检索与用户相关联的类别,那么第一种情况应该没问题,否则您可以考虑第二种情况为用户和类别设置不同的集合,然后引用它们,如下所示:< / p>
var category = { _id: "music"
, name: "Musical Category"
, users: ["jack", "julia", "john"] }
var user = { _id: "jack", name: "Jack", categories: ["music"]}
db.categories.save(category)
db.users.save(user)
db.categories.find({_id: {$in: user.categories}}) // categories for user
db.users.find({_id: {$in: category.users}}) // users for category
但我刚刚触及了架构设计的主题。您必须分析基数和数据访问模式才能获得可靠的设计。 来自Mongo的帖子给出了非常好的解释和示例: http://blog.mongodb.org/post/87200945828/6-rules-of-thumb-for-mongodb-schema-design-part-1
来自手册:http://docs.mongodb.org/manual/applications/data-models/