我有一个基于时间戳的数据集。
Date Value
07-Jul-15 12:05:00 1
07-Jul-15 12:10:00 1
07-Jul-15 12:15:00 1
07-Jul-15 12:20:00 0
07-Jul-15 12:25:00 0
07-Jul-15 12:30:00 0
07-Jul-15 12:35:00 1
07-Jul-15 12:40:00 1
07-Jul-15 12:45:00 1
07-Jul-15 12:50:00 1
07-Jul-15 12:55:00 0
07-Jul-15 13:00:00 0
07-Jul-15 13:05:00 1
07-Jul-15 13:10:00 1
07-Jul-15 13:15:00 1
07-Jul-15 13:20:00 0
07-Jul-15 13:25:00 0
我想查询并返回
- 停机次数：此情况下的停机次数为3，基于0为ON，1为OFF。
每次关闭之间的时间段
示例：
- From：07-Jul-15 12:05:00 To：07-Jul-15 12:15:00持续时间：15分钟
- 来自：07-Jul-15 12:35:00致：07-Jul-15 12:50:00持续时间：20分钟
我正在使用Oracle
答案 0 :(得分：1)
您可以在sqlfiddle上测试我的答案：http://www.sqlfiddle.com/#!4/9c6a69/16
测试数据
create table test (dttm date, onoff number);
insert into test values (to_date('07-Jul-15 12:05:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:10:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:15:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:20:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 12:25:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 12:30:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 12:35:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:40:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:45:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:50:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 12:55:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 13:00:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 13:05:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 13:10:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 13:15:00', 'DD-MM-YY HH24:MI:SS'), 1 );
insert into test values (to_date('07-Jul-15 13:20:00', 'DD-MM-YY HH24:MI:SS'), 0 );
insert into test values (to_date('07-Jul-15 13:25:00', 'DD-MM-YY HH24:MI:SS'), 0 );
首先，删除所有不必要的列并仅保留开/关列：
select t.dttm, t.onoff from test t
where not exists (select 'X' from test tt
where tt.dttm =
(select max(ttt.dttm) from test ttt where ttt.dttm < t.dttm)
and tt.onoff = t.onoff)
停机次数：
with data as (
select t.dttm, t.onoff from test t
where not exists (select 'X' from test tt
where tt.dttm =
(select max(ttt.dttm) from test ttt where ttt.dttm < t.dttm)
and tt.onoff = t.onoff)
)
select count(*) from data d where d.onoff=0;
准时：
with data as (
select t.dttm, t.onoff from test t
where not exists (select 'X' from test tt
where tt.dttm =
(select max(ttt.dttm) from test ttt where ttt.dttm < t.dttm)
and tt.onoff = t.onoff)
)
select d1.dttm as ontime,
d0.dttm as offtime,
(d0.dttm - d1.dttm) * 24 * 60 as duration
from data d0, data d1
where d1.onoff=1
and d0.dttm = (select min(dd0.dttm) from data dd0 where dd0.dttm > d1.dttm);
答案 1 :(得分：1)
在ORACLE中使用LEAD和LAG函数可以构建这些查询：
1.关闭次数：
WITH IntTable AS
( SELECT * FROM
(
SELECT dt b_date,value,LEAD(dt) OVER (ORDER BY dt) e_date FROM
(
select "Date" dt,"Value" value,
LAG("Value") OVER (ORDER BY "Date") pvalue,
LEAD("Value") OVER (ORDER BY "Date") nvalue
from T
) T1
WHERE pvalue is NULL or value<>pvalue or nvalue is NULL
)
WHERE E_DATE is NOT NULL
)
SELECT COUNT(*) FROM IntTable where value = 0
2.每次关闭之间的时间
WITH IntTable AS
( SELECT * FROM
(
SELECT dt b_date,value,LEAD(dt) OVER (ORDER BY dt) e_date FROM
(
select "Date" dt,"Value" value,
LAG("Value") OVER (ORDER BY "Date") pvalue,
LEAD("Value") OVER (ORDER BY "Date") nvalue
from T
) T1
WHERE pvalue is NULL or value<>pvalue or nvalue is NULL
)
WHERE E_DATE is NOT NULL
)
SELECT b_date,e_date, (e_date-b_date) * 60 * 24 FROM IntTable where value = 1
答案 2 :(得分：0)
您的问题有两个部分，两个部分都需要在两个不同的查询中处理。由于输出基于两组不同的行。
<强>设置
SQL> CREATE TABLE t AS SELECT * FROM(WITH DATA(dt, status) AS(
2 SELECT to_date('07-Jul-15 12:05:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
3 SELECT to_date('07-Jul-15 12:10:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
4 SELECT to_date('07-Jul-15 12:15:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
5 SELECT to_date('07-Jul-15 12:20:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
6 SELECT to_date('07-Jul-15 12:25:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
7 SELECT to_date('07-Jul-15 12:30:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
8 SELECT to_date('07-Jul-15 12:35:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
9 SELECT to_date('07-Jul-15 12:40:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
10 SELECT to_date('07-Jul-15 12:45:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
11 SELECT to_date('07-Jul-15 12:50:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
12 SELECT to_date('07-Jul-15 12:55:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
13 SELECT to_date('07-Jul-15 13:00:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
14 SELECT to_date('07-Jul-15 13:05:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
15 SELECT to_date('07-Jul-15 13:10:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
16 SELECT to_date('07-Jul-15 13:15:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 1 FROM dual UNION ALL
17 SELECT to_date('07-Jul-15 13:20:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual UNION ALL
18 SELECT to_date('07-Jul-15 13:25:00', 'dd-Mon-rr hh24:mi:ss', 'NLS_DATE_LANGUAGE=AMERICAN'), 0 FROM dual
19 ) SELECT * FROM DATA);
Table created.
表格数据
SQL> SELECT * FROM t;
DT STATUS
------------------ ----------
07-Jul-15 12:05:00 1
07-Jul-15 12:10:00 1
07-Jul-15 12:15:00 1
07-Jul-15 12:20:00 0
07-Jul-15 12:25:00 0
07-Jul-15 12:30:00 0
07-Jul-15 12:35:00 1
07-Jul-15 12:40:00 1
07-Jul-15 12:45:00 1
07-Jul-15 12:50:00 1
07-Jul-15 12:55:00 0
07-Jul-15 13:00:00 0
07-Jul-15 13:05:00 1
07-Jul-15 13:10:00 1
07-Jul-15 13:15:00 1
07-Jul-15 13:20:00 0
07-Jul-15 13:25:00 0
17 rows selected.
- 停机次数：此情况下的停机次数为3，基于0为ON，1为OFF。
您需要使用 LAG（）分析功能。
SQL> SELECT TO_CHAR(dt, 'dd-Mon-rr hh24:mi:ss') dt,
2 status
3 FROM
4 (SELECT t.*,
5 CASE
6 WHEN lag(status) OVER(ORDER BY dt) <> status
7 THEN 1
8 ELSE 0
9 END chg
10 FROM t
11 )
12 WHERE status = 0
13 AND chg =1;
DT STATUS
------------------ ----------
07-Jul-15 12:20:00 0
07-Jul-15 12:55:00 0
07-Jul-15 13:20:00 0
因此，输出中有3行，这意味着发生了3次关闭事件。要获得计数，您只需使用 COUNT 功能。
- 每次关闭之间的时间段
示例：
- From：07-Jul-15 12:05:00 To：07-Jul-15 12:15:00持续时间：15分钟
- 来自：07-Jul-15 12:35:00致：07-Jul-15 12:50:00持续时间：20分钟
再一次，您需要使用 LAG（）分析功能。日期之间的差异返回天数。要将其转换为分钟数，请将其乘以 24 * 60 。
SQL> SELECT * FROM(
2 SELECT t.*,
3 CASE
4 WHEN lag(status) OVER(ORDER BY dt) <> status
5 THEN 1
6 ELSE 0
7 END chg,
8 24*60*(dt - lag(dt) over(order by dt)) gap
9 FROM t
10 ) t
11 WHERE status =1 and chg =0;
DT STATUS CHG GAP
------------------ ---------- ---------- ----------
07-Jul-15 12:05:00 1 0
07-Jul-15 12:10:00 1 0 5
07-Jul-15 12:15:00 1 0 5
07-Jul-15 12:40:00 1 0 5
07-Jul-15 12:45:00 1 0 5
07-Jul-15 12:50:00 1 0 5
07-Jul-15 13:10:00 1 0 5
07-Jul-15 13:15:00 1 0 5
8 rows selected.
SQL>
因此，根据上述查询，要查找系统启动时的总时间，请使用 SUM 。
SQL> SELECT SUM(gap) on_minutes FROM(
2 SELECT t.*,
3 CASE
4 WHEN lag(status) OVER(ORDER BY dt) <> status
5 THEN 1
6 ELSE 0
7 END chg,
8 24*60*(dt - lag(dt) over(order by dt)) gap
9 FROM t
10 ) t
11 WHERE status =1 and chg =0;
ON_MINUTES
----------
35
SQL>
因此，该系统适用于35 minutes。
答案 3 :(得分：0)
您好我已尝试使用以下代码，它会按预期显示结果
#lang racket
(require math)
(require plot/no-gui)
(plot-file (list (axes)
(inverse-interval (λ (x) 1)
(λ (x) -1)
-3.00000 3.000000)
(function (lambda (x) (* (expt 3 x) (sin (* 20 x)))) -1 1))
"images/plot_000000.jpg"
#:y-min -4
#:y-max 4)