我有类似的东西
<div data-count="5">Something</div>
<div data-count="10">Something</div>
<div data-count="15">Something</div>
<div data-count="20">Something</div>
<div data-count="25">Something</div>
如何删除其中&#34;数据计数&#34;属性值小于15?
答案 0 :(得分:4)
请尝试:
$('div').each(function() {
if ( $(this).attr('data-count') < 15 ) {
$(this).remove();
}
});
答案 1 :(得分:4)
这更有效,因为它只选择div
属性为data-count
,并且只为每个元素构造一次jQuery对象:
$('div[data-count]').each(function () {
var $this = $(this);
if ($this.attr('data-count') < 15) {
$this.remove();
}
});
演示:
$('button').on('click', function () {
$('div[data-count]').each(function () {
var $this = $(this);
if ($this.attr('data-count') < 15) {
$this.remove();
}
});
});
&#13;
div[data-count]:before {
content: "<div data-count=\"" attr(data-count) "\">";
}
div[data-count]:after {
content: "</div>";
}
&#13;
<script src="https://code.jquery.com/jquery-2.1.4.min.js"></script>
<button type="button">Remove data-count less than 15</button>
<div data-count="5">Something</div>
<div data-count="10">Something</div>
<div data-count="15">Something</div>
<div data-count="20">Something</div>
<div data-count="25">Something</div>
&#13;
原生JavaScript中的替代解决方案:
var divs = document.querySelectorAll('div[data-count]'),
div, i;
for (i = 0; i < divs.length; i++) {
div = divs[i];
if (div.getAttribute('data-count') < 15) {
// this will not affect iteration because querySelectorAll is a non-live NodeList
div.parentNode.removeChild(div);
}
}
演示:
var button = document.querySelector('button');
button.addEventListener('click', function () {
var divs = document.querySelectorAll('div[data-count]'),
div, i;
for (i = 0; i < divs.length; i++) {
div = divs[i];
if (div.getAttribute('data-count') < 15) {
// this will not affect iteration because querySelectorAll is a non-live NodeList
div.parentNode.removeChild(div);
}
}
});
&#13;
div[data-count]:before {
content: "<div data-count=\"" attr(data-count) "\">";
}
div[data-count]:after {
content: "</div>";
}
&#13;
<button type="button">Remove data-count less than 15</button>
<div data-count="5">Something</div>
<div data-count="10">Something</div>
<div data-count="15">Something</div>
<div data-count="20">Something</div>
<div data-count="25">Something</div>
&#13;
答案 2 :(得分:2)
这可能不是最有效的方法,但它有效:
function removeLowData() {
for(var i = 1; i < 15; i++) {
var elements = $("[data-count='" + i + "']");
for(var j = 0; j < elements.length; j++) {
$(elements[j]).remove();
//or use .hide() if you still want them to be part of the dom but not visible
}
}
}
只要您需要移除div
,只需致电removeLowData()
即可