Question

def main():

    infile = open("studentinfo.txt", "rt")
    data = infile.read()
    fName, lName, ID, year = data.split(",")
    year = int(year)

    # Prompt the user for three test scores
    grades = eval(input("Enter the three test scores separated by a coma: "))
    # Prompt create a username
    uName = (lName[:4] + fName[:2] + str(year)).lower()
    converted_id = ID[:3] + "-" + ID[3:5] + "-" + ID[5:]
    grade_1, grade_2, grade_3 = grades
    # Convert the grades to strings so they can be written to a new file
    [grade_1, grade_2, grade_3] = [str(grade_1), str(grade_2), str(grade_3)]
    # Calculate the average
    average =(float(grade_1) + float(grade_2)+ float(grade_3))/3.0
    # Convert the average to a string
    average = str(average)
    # Write the information to the file
    outfile = open("studentreport.txt", "w")
    outfile.write("*******Student Report*******\nStudent Name:" + fName + " " + lName)
    outfile.write("\nStudent ID:  " + converted_id + "\n" + "Username:    " + uName + "\n\n")
    outfile.write("Grade 1:    " + str(grade_1) + "\n" "Grade 2:    " + str(grade_2) + "\n" + "Grade 3:    " + str(grade_3) + "\n" + "Average:    " + str(average))   

    infile.close()
    outfile.close()

main()

如何使用可读的文本文件使其正常运行这是我运行程序帮助时得到的全部内容吗？

Enter the three test scores separated by a coma: 80,78,90,
>>> 80,78,90,
(80, 78, 90)
>>> main()
Enter the three test scores separated by a coma: 87,86,90
>>>

Answer 1

可能存在一些语法问题，但我无法测试它，因为我没有您的文件，但这可能与您的想法一致：

def get_grades(student_name):
    grades = raw_input("Enter the three test scores for {0} separated by a coma: ".format(student_name)).split(',')
    if len(grades) != 3:
        print "must enter three grades"
        return get_grades(student_name)
    return float(grades[0]), float(grades[1]), float(grades[2])

with open("studentreport.txt", "w") as outfile:
    outfile.write("*******Student Report*******\n")
    with open("studentinfo.txt", "r") as infile:
        for student in infile:
            fName, lName, ID, year = student.split(",")
            year = int(year)
            uName = "{0}{1}{2}".format(lName[:4], fName[:2], str(year)).lower()
            converted_id = "{0}-{1}-{2}".format(ID[:3], ID[3:5], ID[5:])

            # Prompt the user for three test scores
            grade_1, grade_2, grade_3 = get_grades("{0} {1}".format(fName, lName))
            average = sum([grade_1, grade_2, grade_3])/3
            outfile.write("Student Name:{0} {1}\n".format(fName, lName))
            outfile.write("Student ID:  {0}\nUsername:    {1}\n\n".format(converted_id, uName))
            outfile.write("Grade 1:    {0}\nGrade 2:    {1}\nGrade 3:    {2}\nAverage:    {3}\n\n".format(grade_1, grade_2, grade_3,average))

用输入测试：

sam, snead, kghasjkdfiuaski21, 2006
john, doe, 9792345678872, 2009
garth, nroken, 097892364, 2006

输出：

*******Student Report*******
Student Name:sam  snead
Student ID:   kg-ha-sjkdfiuaski21
Username:     snesa2006

Grade 1:    56.0
Grade 2:    67.0
Grade 3:    78.0
Average:    67.0

Student Name:john  doe
Student ID:   97-92-345678872
Username:     doejo2009

Grade 1:    67.0
Grade 2:    89.0
Grade 3:    78.0
Average:    78.0

Student Name:garth  nroken
Student ID:   09-78-92364
Username:     nroga2006

Grade 1:    45.0
Grade 2:    67.0
Grade 3:    89.0
Average:    67.0

请记住： Eval是邪恶的

如何将可读文本文件输入到我的Python代码中并使其正常运行

1 个答案: