Question

我一直试图通过按钮激活的线程来实现这个简单的例子。它基于以下问题中的解决方案：

How to implement frequent start/stop of a thread (QThread)

上面的示例解决方案与我的代码之间的主要区别是：

我使用了QWidget而不是MainWindow
为清晰起见，我更改了信号名称
我的代码包含调试信息
我尝试消除工人创造的信号，因为没有做任何事情

看起来启动/停止信号没有触发相应的插槽，但我没有足够的经验来解决原因。

此外，我不确定信号的目的：

SignalToObj_mainThreadGUI（）

这只是可以使用的东西而不是吗？

我一直试图让这段代码工作一段时间，所以任何帮助都会非常感激。

的main.cpp

#include "threadtest.h"
#include <QApplication>

int main(int argc, char *argv[]) 
{
    QApplication a(argc, argv);
    ThreadTest w;
    w.show();

    return a.exec(); 
}

threadtest.h

#include <QWidget>
#include <QThread>
#include "worker.h"     

namespace Ui 
{
    class ThreadTest;
}

class ThreadTest : public QWidget
{
    Q_OBJECT

public:
    explicit ThreadTest(QWidget *parent = 0);
    ~ThreadTest();

signals:
    void startWorkSignal();
    void stopWorkSignal();


private slots:
    void on_startButton_clicked();
    void on_stopButton_clicked();

private:
    Ui::ThreadTest *ui;
    worker *myWorker;
    QThread *WorkerThread;
};

threadtest.cpp

#include "threadtest.h"
#include "ui_threadtest.h"

ThreadTest::ThreadTest(QWidget *parent) :
QWidget(parent),
ui(new Ui::ThreadTest) 
{
    ui->setupUi(this);

    myWorker = new worker;
    WorkerThread = new QThread;
    myWorker->moveToThread(WorkerThread);

    connect(this,
            SIGNAL(startWorkSignal()),
            myWorker,
            SLOT(StartWork())
            );

    connect(this,
            SIGNAL(stopWorkSignal()),
            myWorker,
            SLOT(StopWork())
            );

    //Debug
    this->dumpObjectInfo();
    myWorker->dumpObjectInfo(); 
}

ThreadTest::~ThreadTest() 
{
    delete ui; 
}

void ThreadTest::on_startButton_clicked() 
{
    qDebug() << "startwork signal emmitted";
    emit startWorkSignal(); 
}

void ThreadTest::on_stopButton_clicked() 
{
    qDebug() << "stopwork signal emmitted";
    emit stopWorkSignal(); 
}

worker.h

#include <QObject>
#include <QDebug>

class worker : public QObject {
    Q_OBJECT 
public:
    explicit worker(QObject *parent = 0);
    ~worker();

signals:
    void SignalToObj_mainThreadGUI();
    //void running();
    //void stopped();

public slots:
    void StopWork();
    void StartWork();

private slots:
    void do_Work();

private:
    volatile bool running, stopped; 
};

worker.cpp

#include "worker.h"

worker::worker(QObject *parent) : QObject(parent), stopped(false),
running(false) 
{
    qDebug() << "running: " << running;
    qDebug() << "stopped: " << stopped; 

}


worker::~worker() {}

void worker::do_Work() 
{
    qDebug() << "inside do Work";
    emit SignalToObj_mainThreadGUI();

    if (!running || stopped) return;

    // actual work here
    /*
    for (int i = 0; i < 100; i++)
    {
        qDebug() << "count: " + i;
    }
    */
    QMetaObject::invokeMethod(this, "do_Work", Qt::QueuedConnection); 
}

void worker::StopWork() 
{
    qDebug() << "inside StopWork";
    stopped = true;
    running = false;

    //emit stopped(); 
}

void worker::StartWork() 
{
    qDebug() << "inside StartWork";
    stopped = false;
    running = true;

    //emit running();
    do_Work(); 
}

Answer 1

不会触发插槽，因为您已将myWork移动到线程WorkerThread，但未在该线程中运行事件循环。在threadtest.cpp中，添加

WorkerThread .start();

后

myWorker = new worker;
WorkerThread = new QThread;
myWorker->moveToThread(WorkerThread);

Answer 2

你应该写

WorkerThread->start();

或者您可以使用ThreadTest对象的线程而不是WorkerThread（在这种情况下，WorkerThread是不必要的）：

 myWorker->moveToThread(thread()); // this->thread

Qt - 使用按钮控制的线程的简单示例

2 个答案: