Question

当我选择表格时

Select 
    [Premium Amount], [Policy Number], 
    [Transaction Type Code], Insured, * 
from 
    DW.Table
where 
    [Policy Number] in ('1111111111', '2222222222')

这些是结果。

Premium Amount  Policy Number   Transaction Type Code      Insured
-12798.0000     1111111111       Cancellation              ABC Group
27000.0000      1111111111       Renewal Business          ABC Group 
-8452.7700      2222222222       Cancellation              DEF Group
10221.0000      2222222222       Renewal Business          DEF Group

我想要发生的是创建两个新列，[Original Policy Premium]和[Transaction Premium]。

[原始保单保费]是一个列，其中包含交易类型代码=续订业务时，它将导致相应的保费金额= 27000.0000，保单号为111111111 。同样适用于政策号22222222.

让它看起来像这样。

Original Policy Premium  Transaction Premium  Policy Number   
27000.0000                -12798.0000          1111111111
10221.0000                -8452.7700           2222222222

Select 
    case 
       when [Transaction Type Code] = 'Renewal Business' 
         then [Premium Amount] 
         else '' 
    end as [Original Policy Premium],
    case 
      when [Transaction Type Code] = 'Cancellation' 
        then [Premium Amount] 
        else '' 
    end as [Transaction Premium],
    [Policy Number], 
    [Transaction Code] 
from 
    DW.Table
where 
    [Policy Number] in ('111111111', '22222222')

但是我跑完后得到了这个错误。

Msg 8114，Level 16，State 5，Line 1
将数据类型varchar转换为数字时出错。

但是当我用“END AS NULL”替换END作为''时

Original Policy Premium  Transaction Premium   Policy Number   
    27000.0000                NULL             1111111111
    NULL                     -12798.0000       1111111111
    10221.0000                NULL             2222222222
    NULL                     -8452.7700        2222222222

Answer 1

您的案例路径返回不同的类型。它们必须是同一类型。改为：

select max(case when [Transaction Type Code] = 'Renewal Business'
                then [Premium Amount] 
                else null end) as [Original Policy Premium],
       max(case when [Transaction Type Code] = 'Cancellation'
                then [Premium Amount] 
                else null end) as [Transaction Premium],
       [Policy Number]
from table
where [Policy Number] in ('111111111', '22222222')
group by [Policy Number]

使用案例函数

1 个答案: