Question

def get_time():
    start_time = str(input("Please enter the time you started working (hh:mm) "))
    if ":" in start_time:
        h1, m1 = start_time.split(":")
    else:
        h1 = int(start_time)
        m1 = " "
    if h1 < 8:
        print("You can't start working until 08:00.")
    elif h1 > 23:
        print("You can't work past 24:00 (midnight) ")
    end_time = str(input("Please enter the time you stopped working (hh:mm) "))

get_time()

这是我的一个程序的代码，我打算接受有人照顾的时间。我无法将字符串数字转换回整数。我收到错误：

  File "/Applications/Python 3.4/babysitting.py", line 10, in get_time
    if h1 < 8:
TypeError: unorderable types: str() < int()

为什么没有h1 = int(start_time)工作？

Answer 1

为什么h1 = int(start_time)没有工作？

当输入中有:个字符时，该行根本没有被执行：

if ":" in start_time:
    h1, m1 = start_time.split(":")
else:
    h1 = int(start_time)
    m1 = " "

当输入中没有int(start_time)时，:仅执行 ，因此当if测试为假时。

分离拆分和整数转换：

h1 = start_time if ":" in start_time: h1 = start_time.split(":")[0] h1 = int(h1)

无法在Python 3

1 个答案: