bannedWord = ['Good','Bad','Ugly']
def RemoveBannedWords(toPrint,database):
statement = toPrint
for x in range(0,len(database)):
if bannedWord[x] in statement:
statement = statement.replace(bannedWord[x]+' ','')
return statement
toPrint = 'Hello Ugly Guy, Good To See You.'
print RemoveBannedWords(toPrint,bannedWord)
输出为Hello Guy, To See You.
了解Python我觉得有更好的方法来实现更改字符串中的多个单词。我使用字典搜索了一些类似的解决方案,但它似乎不适合这种情况。
答案 0 :(得分:10)
我用
bannedWord = ['Good','Bad','Ugly']
toPrint = 'Hello Ugly Guy, Good To See You.'
print ' '.join(i for i in toPrint.split() if i not in bannedWord)
答案 1 :(得分:6)
这是一个使用正则表达式的解决方案:
import re
def RemoveBannedWords(toPrint,database):
statement = toPrint
pattern = re.compile("\\b(Good|Bad|Ugly)\\W", re.I)
return pattern.sub("", toPrint)
toPrint = 'Hello Ugly Guy, Good To See You.'
print RemoveBannedWords(toPrint,bannedWord)
答案 2 :(得分:0)
主题的又一个变体。如果你要打电话给这个,那么最好先编译一次正则表达式:
import re
bannedWord = ['Good','Bad','Ugly']
re_banned_words = re.compile(r"\b(" + "|".join(bannedWord) + ")\\W", re.I)
def RemoveBannedWords(toPrint):
global re_banned_words
return re_banned_words.sub("", toPrint)
toPrint = 'Hello Ugly Guy, Good To See You.'
print RemoveBannedWords(toPrint)
答案 3 :(得分:0)
Ajay的代码略有变化,当其中一个字符串是bannedWord列表中其他字符串的子字符串时
bannedWord = ['good', 'bad', 'good guy' 'ugly']
toPrint ='good winter good guy'
的结果将是
RemoveBannedWords(toPrint,database = bannedWord) = 'winter good'
因为它会首先删除good
。需要对列表中的元素长度进行排序。
import re
def RemoveBannedWords(toPrint,database):
statement = toPrint
database_1 = sorted(list(database), key=len)
pattern = re.compile(r"\b(" + "|".join(database_1) + ")\\W", re.I)
return pattern.sub("", toPrint + ' ')[:-1] #added because it skipped last word
toPrint = 'good winter good guy.'
print(RemoveBannedWords(toPrint,bannedWord))
答案 4 :(得分:0)
当您检查开头的单词边界和结尾的非单词字符时,最好使用正则表达式。 仍然可以使用内存中的数组/列表
bannedWord = ['Good', 'Bad', 'Ugly']
toPrint = 'Hello Uglyyy Guy, Good To See You.'
for word in bannedWord:
toPrint = toPrint.replace(word, "")
print(toPrint)
Hello yy Guy, To See You.
[Program finished]