是否存在std :: tie for std :: pair之类的东西？

Question

例如，使用元组：

#include <tuple>        // std::tuple, std::make_tuple, std::tie

int num;
char letter;
std::tuple<int,char> num_letter;

num_letter = std::make_tuple(10, 'a');
std::tie(num, letter) = num_letter;  // unpack num_letter into num and letter

是否有对等的东西？

// ...
num_letter = std::make_pair(10, 'a');
std::pair_tie(num, letter) = num_letter;

Answer 1

实际上，对的代码完全相同，因为std::tuple有operator = with std::pair as an argument。

num_letter = std::make_pair(10, 'a');
std::tie(num, letter) = num_letter;