Question

好的，这看起来是一个重复的问题，然而，我一直在寻找这个超过2天但没有成功。以下是配置详细信息：

带注释的App Config类

@Configuration
@ComponentScan(basePackages = "com.test")
@EnableTransactionManagement(mode=AdviceMode.PROXY, proxyTargetClass=true)
public class AnnotatedAppConfig {

private static final Logger _logger = Logger
        .getLogger(AnnotatedAppConfig.class);

@Bean
public DataSource dataSource() {
    // C3P0 datasource configuration
    final ComboPooledDataSource dataSource = new ComboPooledDataSource();
    try {
        dataSource.setDriverClass(ReaderUtil.getInstance()
                .getProperty(IConst.DB_DRIVER));
    } catch (PropertyVetoException e) {
        _logger.error("Error setting driver class ", e);
    }
    dataSource.setUser(ReaderUtil.getInstance().getProperty(
            IConst.DB_USER));
    dataSource.setPassword(ReaderUtil.getInstance().getProperty(
            IConst.DB_PASSWORD));
    dataSource.setJdbcUrl(ReaderUtil.getInstance().getProperty(
            IConst.DB_URL));

    _logger.info("Datasource created successfully");
    return dataSource;
}

@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
    final LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new LocalContainerEntityManagerFactoryBean();
    entityManagerFactoryBean.setDataSource(dataSource());
    entityManagerFactoryBean.setPersistenceUnitName("testunit");
    entityManagerFactoryBean.setJpaVendorAdapter(createJPAVendorAdapter());

    _logger.info("EntityManagerFactory created successfully");
    return entityManagerFactoryBean;
}

@Bean
public PlatformTransactionManager txManager() {
    final JpaTransactionManager transactionManager = new JpaTransactionManager();
    transactionManager.setEntityManagerFactory(entityManagerFactory()
            .getObject());
    transactionManager.setDataSource(dataSource());

    _logger.info("Transaction Manager created successfully");
    return transactionManager;
}

private HibernateJpaVendorAdapter createJPAVendorAdapter() {
    final HibernateJpaVendorAdapter jpaVendorAdapter = new HibernateJpaVendorAdapter();
    jpaVendorAdapter.setShowSql(true);
    jpaVendorAdapter.setGenerateDdl(false);
    jpaVendorAdapter.setDatabase(Database.MYSQL);
    jpaVendorAdapter.setDatabasePlatform(ReaderUtil.getInstance()
            .getProperty(IConst.HIBERNATE_DB_DIALECT));
    return jpaVendorAdapter;
    }
}

带注释的服务类

@Service
@Transactional(value="txManager")
public class TestServiceImpl extends BaseServiceImpl implements ITestService {

@Autowired
private ITestDAO testDAO;

@Override
@Transactional(propagation=Propagation.REQUIRES_NEW, readOnly=false, value="txManager")
public Long register(final String username, final String password,
        final String name, final String address, final Integer deptId) {
    return testDAO.register(username, password, name, address, deptId);
    }
}

当我尝试调用register方法时，抛出以下错误（在DEBUG模式下）：

TransactionAspectSupport.completeTransactionAfterThrowing（534）|在异常之后完成[com.test.service.TestServiceImpl.register]的事务：javax.persistence.TransactionRequiredException： 没有正在进行的事务 2015年7月7日18:59:36,488 230371 [http-bio-9080-exec-5]：DEBUG - RuleBasedTransactionAttribute.rollbackOn（131）|应用规则来确定事务是否应该在javax.persistence.TransactionRequiredException上回滚：没有事务正在进行中

我已经尝试了所有我能在网上找到的东西，但是，没有运气。任何专家，请帮助我了解配置中缺少的内容。

请注意：自动装配工作正常，读取事务（SELECT查询）工作正常。

我读到@Service＆amp;如果在同一个类上一起应用，则@Transactional注释不起作用（在我的情况下发生，TestServiceImpl同时具有注释）。是这样的吗？在这种情况下，解决方法是什么？

带有JPA的Spring 4（Hibernate实现）：事务无法正常工作（没有正在进行的事务）

0 个答案: