Question

在下面的示例代码段中，我有一些需要编辑的JSON（超过1400个条目）。我需要做两件事：

在此示例行中：“phone”：“+ 44 2079693900”，我需要删除+44和2079693900之间的空格，但是对于所有记录。导致：“+ 442079693900”
对于纬度和经度，我需要摆脱数字周围的双引号，因为我使用的API只接受这些值作为浮点数。示例：“latitude”：“51.51736”，需要：“纬度”：51.51736

我最熟悉Ruby，并且过去已经对此进行了一些JSON解析，但我认为Regex将是用于此类基本数据清理任务的最佳工具。我已经提到了regex101.com和regular-expressions.info，但我现在很困惑。提前谢谢！

[
  {
    "id": "101756",
    "name": "1 Lombard Street
    "email": "reception@1lombardstreet.com",
    "website": "http://www.1lombardstreet.com",
    "location": {
      "latitude": "51.5129",
      "longitude": "-0.089",
      "address": {
        "line1": "1 Lombard Street",
        "line2": "",
        "line3": "",
        "postcode": "EC3V 9AA",
        "city": "London",
        "country": "UK"
      }
    }
  },
  {
    "id": "105371",
    "name": "108 Brasserie",
    "phone": "+44 2079693900",
    "email": "enquiries@108marylebonelane.com",
    "website": "http://www.108brasserie.com",
    "location": {
      "latitude": "51.51795",
      "longitude": "-0.15079",
      "address": {
        "line1": "108 Marylebone Lane",
        "line2": "",
        "line3": "",
        "postcode": "W1U 2QE",
        "city": "London",
        "country": "UK"
      }
    }
  },
  {
    "id": "108701",
    "name": "1901 Restaurant",
    "phone": "+44 2076187000",
    "email": "london.restres@andaz.com",
    "website": "http://www.andazdining.com",
    "location": {
      "latitude": "51.51736",
      "longitude": "-0.08123",
      "address": {
        "line1": "Andaz Hotel",
        "line2": "40 Liverpool Street",
        "line3": "",
        "postcode": "EC2M 7QN",
        "city": "London",
        "country": "UK"
      }
    }
  },
  {
    "id": "102190",
    "name": "2 Bridge Place",
    "phone": "+44 2078028555",
    "email": "fb@dtlondonvictoria.com",
    "website": "http://crimsonhotels.comdoubletreelondonvictoriadiningpre-theatre-dining",
    "location": {
      "latitude": "51.49396",
      "longitude": "-0.14343",
      "address": {
        "line1": "2 Bridge Place",
        "line2": "Victoria",
        "line3": "",
        "postcode": "SW1V 1QA",
        "city": "London",
        "country": "UK"
      }
    }
  },
  {
    "id": "102063",
    "name": "2 Veneti",
    "phone": "+44 2076370789",
    "email": "2veneti@btconnect.com",
    "website": "http://www.2veneti.com",
    "location": {
      "latitude": "51.5168",
      "longitude": "-0.14673",
      "address": {
        "line1": "10 Wigmore Street",
        "line2": "",
        "line3": "",
        "postcode": "W1U 2RD",
        "city": "London",
        "country": "UK"
      }
    }
  },

Answer 1

您可以使用以下正则表达式：

("phone":\s*"\+44)\s+|("(?:latitude|longitude)":\s*)"([^"]+)"

进行以下替换：

$1$2$3

我们的想法是捕获我们想要的东西而不是捕获我们不想要的东西，然后使用反向引用来恢复我们想要保留的子串。

正则表达式解释：

该模式包含2个与|交替运算符连接的备选方案：

("phone":\s*"\+44)\s+：
- ("phone":\s*"\+44) - 第一个匹配文字"phone": +可选空格的捕获组，然后是+44字面意思
- \s+ - 我们将删除的一个或多个空格
("(?:latitude|longitude)":\s*)"([^"]+)"：
- ("(?:latitude|longitude)":\s*) - 匹配"latitude":或"longitude":以及0个或更多空白字符的第二个捕获组
- " - 文字"，我们会放弃
- ([^"]+) - 第三个捕获组匹配"以外的一个或多个字符（我们会保留该字符）
- " - 再次，我们将放弃的文字"。

请参阅demo

在带有正则表达式的JSON字符串中删除+44之后的空格和lat / long周围的引号

1 个答案: