我正在尝试将纯Java代码转换为swift.But,我在设置当前时间时遇到了一些问题。我可以用毫秒来获取当前时间。但我无法设置当前时间。对此有何帮助?
这是我的代码
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
let now = NSDate()
var auctionDate = [String:String]()
let dateFormatter = NSDateFormatter()
dateFormatter.locale = NSLocale(localeIdentifier: "en_US")
var sdfDDMMYYYYEEE : NSDateFormatter!
sdfDDMMYYYYEEE.dateFormat = "dd/MM/yyyy (EEE)"
var sdfDDMMYYYY : NSDateFormatter!
sdfDDMMYYYY.dateFormat = "dd/MM/yyyy"
var sdfEEE : NSDateFormatter!
sdfEEE.dateFormat = "EEE"
// This is how i get the current time
println((now.timeIntervalSince1970)*1000 + 86400000.00)
for var i = 0; i < 5; i++ {
if sdfEEE.stringFromDate(now) == "Sun" {
// This is where i have to set my time with that ((now.timeIntervalSince1970)*1000 + 86400000.00)
i--;
continue;
}
auctionDate[(sdfDDMMYYYY.stringFromDate(now) as String)] = (sdfDDMMYYYYEEE.stringFromDate(now) as String)
// Here too I have to set my time
}
println(dateFormatter.stringFromDate(now))
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
这是我要转换为swift代码的java代码
import java.text.*;
import java.util.*;
public class DateTest{
Date now = new Date();
Map<String, String> myDate = new LinkedHashMap<String, String>();
myDate.put("", "All");
SimpleDateFormat sdfDDMMYYYYEEE = new SimpleDateFormat("dd/MM/yyyy (EEE)");
SimpleDateFormat sdfDDMMYYYY = new SimpleDateFormat("dd/MM/yyyy");
SimpleDateFormat sdfEEE = new SimpleDateFormat("EEE");
for (int i = 0; i < 5; i++) {
if (sdfEEE.format(now).equals("Sun")) {
now.setTime(now.getTime() + 86400000);
i--;
continue;
}
myDate.put(sdfDDMMYYYY.format(now), sdfDDMMYYYYEEE.format(now));
now.setTime(now.getTime() + 86400000);
}
}
在swift中设置当前时间的任何帮助。我几乎接近我的答案。
答案 0 :(得分:0)
在您的代码中,您希望在1970年以后添加秒数。您很幸运,有一个初始化程序:NSDate(timeIntervalSince1970: NSTimeInterval)
let now = NSDate(timeIntervalSince1970: 86400000)
这将创建一个新的NSDate
并添加86400000
秒,直到1970年以来的秒数。