计算sql中一行的多个值

Question

我有一张包含以下数据集的表

ID      ReportID    RecIDs

7083    52682      47407,47505,33648,47412,
4419    52749      47412,47218,36636,47866,47669,47505,47259,
7496    52883      47488,
6547    52936      47345,47236,47407,33648,47512,47412,47254,47274,36636,
6225    53066      47412,36636,47236,47254,47367,33648,
2733    53067      47218,47221,47236,33648,47866,36636,33595,39485,
6923    53084      37061,47412,47407,47376,47274,47505,47651,47820,

我想编写一个查询，它将为我提供RedIDs列中所有逗号分隔条目的计数。 就像行id 6923

的RecID值的计数一样

Answer 1

您可以使用REPLACE：

SELECT ID, ReportID, RecIDs,
       LEN(RecIDs) - LEN(REPLACE(RecIDs, ',', '')) AS cnt
FROM mytable
WHERE ID = 6923

这会计算','列中RecIDs的数量。这应该等于其中的数字。

Answer 2

SELECT SUM(len(RecIDs) - len(replace(RecIDs, ',', '')) +1) 
    AS RedIDs
FROM DBTABLE