Spring mvc无法获得表单参数

时间:2015-07-07 05:40:24

标签: java spring

下面是我的代码,对于查询方法总是得到null,我不知道为什么会这样。我可以通过其他方式获取表单参数,例如@RequestParam等。我是否需要在XML文件中设置Phone Class的配置?如果是这样,我如何在XML中配置Phone Class?我的XML是recharge-servlet.xml。

以下是控制器:

package com.nu.template.recharge;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;


@Controller
@RequestMapping("/mobile")

public class XJMobile {

    @RequestMapping(value = "/index", method = RequestMethod.GET)
    public ModelAndView getIndexPage() {
        ModelAndView mav = new ModelAndView("recharge");
        return mav;
    }


    @RequestMapping(value = "/query", method = RequestMethod.POST)
    public String query(Phone phone) {
        System.out.println(phone.getNumber());

        return "helloworld";
    }   

}

形式:

<form action="query" method="POST" name="phone_form">
    <section>
        <label>phone:</label>
        <input type="text" name="phone_number" />
    </section>

    <input type="submit" value="submit">
</form>

电话类:

package com.nu.template.recharge;

public class Phone {
    private String phone_number;

    public String getNumber() {
        return this.phone_number;
    }

    public void setNumber(String phone_number) {
        this.phone_number = phone_number;
    }
}

充值-servlet.xml中:

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans      http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">

<mvc:annotation-driven />

<context:component-scan base-package="com.nu.template.recharge"/>

<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
   <property name="prefix" value="/WEB-INF/view/"/>
   <property name="suffix" value=".jsp"/>
</bean>

1 个答案:

答案 0 :(得分:0)

您可以通过

初始化Phone对象
@RequestMapping(value = "query", method = RequestMethod.POST)
public String query(@RequestParam("phone_number") Phone phone) {
    System.out.println(phone.getNumber());

    return "helloworld";
} 

Spring通常会为绑定查找相同的参数类型,或者您可以告诉它与您的pojo绑定,给定一个接受参数类型的setter方法。