Question

我有以下OrientDB SQL查询，它返回用户#12:0所有朋友的用户名和国家/地区。

select 
   username, country 
from (select 
         expand( both('friends') ) 
      from 
         users 
      where 
         @rid = #12:0)

但是，friends边缘的属性years带有整数。我只希望那些#12:0的朋友friends.years > 3。

我试过了

SELECT username, country from (SELECT expand(outE('friends')[years > 3].inV()) FROM #12:0)

SELECT username, country from (SELECT expand(both('friends')[years = 2]) FROM #12:0)

和同一查询的各种游戏。

谢谢，全部！

Answer 1

create class User extends V
create property User.username string
create property User.country string

create class friends extends E
create property friends.year integer  


create vertex User content {'username':'u1', 'country':'PT'}
create vertex User content {'username':'f1', 'country':'AW'}
create vertex User content {'username':'f2', 'country':'CN'}

create edge friends 
from (select from User where username = 'u1')
to (select from User where username = 'f1')
content {'years':3}

create edge friends 
from (select from User where username = 'f2')
to (select from User where username = 'u1')
content {'years':4}

我相信这是你的情况。你可以：

select expand(bothE('friends')[years = 3].inV()) 
from (select from User where username = 'u1')

但是，据我所知，还不支持以下内容：

select expand(bothE('friends')[years > 3].inV()) 
from (select from User where username = 'u1')

Answer 2

另一种选择是将核心查询与另一个嵌套查询包装在一起：

select * from (
select expand(both('friends')) 
from (select from User where username = 'u1')
)
where years > 3

在子查询中按属性过滤边缘 - orientdb sql

2 个答案: