与How to output event source Class Name in serilog RollingFile outputTemplate?类似,而不是在日志文件(outputTemplate
)中,我想命名该文件。
此外,我尝试在使用WriteTo.LiterateConsole + WriteTo.RollingFile
和WriteTo.NLog
之间切换,维护该自定义上下文。
但是,要完成自定义滚动文件命名,我基本上需要在logger初始化时提供名称,如下所示:
var c = new LoggerConfiguration()
.Enrich.WithProperty(/* some standard stuff */)
.WriteTo.LiterateConsole(minLevel)
.WriteTo.RollingFile(string.IsNullOrEmpty(customName) ? "logs\log-{Date}.txt" : "logs\"+customName+".log.{Date}.txt") // <-- would have thought I could use `{SourceContext}` as placeholder...
.CreateLogger()
.ForContext(Constants.SourceContextPropertyName, customName) // <-- not sure if I need this here
;
我想在附加NLog
时做类似的事情,所以我可以利用现有的NLog配置行:
archiveFileName="${basedir}/logs/archives/${logger}.log.{#####}.txt"
初始化如下:
var c = new LoggerConfiguration()
.Enrich.WithProperty(/* some standard stuff */)
.Enrich.WithProperty(Constants.SourceContextPropertyName, customName) // <-- is this the trick?
.WriteTo.Nlog(minLevel)
.CreateLogger()
.ForContext(Constants.SourceContextPropertyName, customName) // <-- not sure if this is redundant with enrichment above
;