删除除最近100行之外的所有行

Question

我正在使用MS SQL数据库，我有一个名为＆＃34; Logs＆＃34;看起来像这样：

这里一个接一个地添加记录，所以几天/几周之后桌子会变得很大。

我需要定期做的是稍微清理一下。即我需要一个SQL查询来删除旧行，并且只保留此表中最近的100条记录。

我同意最好让它删除早于some_date的记录＆＃34; ...之前就是这样，但客户希望它不同:(所以......我们在这里。< / p> 顺便说一句：我对那些对这个问题不屑一顾的人感到有些失望。它有什么问题或者是什么？... 想象一下：这个问题产生了4个答案！ ......一个人决定对此投反对票！现在我真的不知道该怎么想......周围的人很奇怪：（

Answer 1

您可以使用以下其中一项：

-- offset clause
WITH goners AS (
    SELECT *
    FROM Logs
    ORDER BY DateTime DESC
    OFFSET 100 ROWS 
)
DELETE FROM goners

-- numbered rows
WITH goners AS (
    SELECT ROW_NUMBER() OVER(ORDER BY DateTime DESC) AS rn, Logs.*
    FROM Logs
)
DELETE FROM goners
WHERE rn > 100

-- nth value
-- note that this "keeps" all rows that tie for last place
DELETE FROM Logs
WHERE DateTime < (
    SELECT MIN(DateTime)
    FROM (
        SELECT TOP 100 DateTime
        FROM Logs
        ORDER BY DateTime DESC
    ) AS x
)

Answer 2

虽然我同意其他人认为这可能不是一条路，但无论如何，这是一种方法：

;WITH keepers AS
(   SELECT TOP 100 [DateTime]
    FROM dbo.Logs
    ORDER BY [DateTime] DESC )
DELETE FROM dbo.Logs a
WHERE NOT EXISTS ( SELECT 1 FROM keepers b WHERE b.[DateTime] = a.[DateTime] )

Answer 3

不要使用NOT EXISTS，只需使用>=：

WITH keepers AS (
    SELECT TOP 100 [DateTime]
    FROM dbo.Logs
    ORDER BY [DateTime] DESC
   )
DELETE FROM dbo.Logs a
    WHERE l.DateTime < (SELECT MIN([DateTime]) FROM keepers);

我不确定是否存在可以在delete运行时添加新行的锁定设置。如果是这样，这仍然是安全的。

您实际上可以在SQL Server 2012 +中简化此操作：

DELETE FROM dbo.Logs a
    WHERE l.DateTime < (SELECT [DateTime] 
                        FROM dbo.logs
                        ORDER BY [DateTime]
                        OFFSET 99 FETCH FIRST 1 ROW ONLY
                       );

Answer 4

这对我有用：

;with cte as(select top(select count(*) - 100 from table) * from table order by dt)
delete from cte

Answer 5

DECLARE @cutoff DATETIME
SELECT TOP 100 @cutoff = [DateTime] FROM Logs ORDER BY [DateTime] DESC
DELETE FROM Logs WHERE [DateTime] < @cutoff