Question

所以我有一个看起来像这样的字符串：

var sentence = "1 is less than 2";

然后我有关键词的数组：

var array = ["is less than", "is bigger than"];

现在我想使用空格分割变量句子但忽略关键词：

var sentenceArray = ["1", "is less than" , "2"];

任何线索我该怎么办？

好的我很抱歉让这看起来像一个懒惰的问题，因此，我已经制作了一个带有分割的正则表达式，可用于匹配具有多个分隔符的句子。没什么好复杂的，但看起来很干净。享受：

var sentence = "1 is less than 2 and 3";
var sentenceArray = [];
sentenceArray = sentence.split(/(\is less than|and)/g);
alert(sentenceArray);

Answer 1

你在这里。我认为你在JS中的数组是错误的。

var sentence = "1 is less than 2";
var array = ["is less than", "is bigger than"];
var result = [];
for (var i = 0; i < array.length; i++) {
    if (sentence.indexOf(array[i]) > -1) {
        result.push(array[i]);
        var splitResults = sentence.split(array[i]);
        for (var j = 0; j < splitResults.length; j++) {
            result.push(splitResults[j]);
        }
    }
}
alert(result);

希望得到这个帮助。

Answer 2

假设你的array是字符串数组（我省略了那些花括号），你可以这样做：

var sentence = "1 is less than 2";
var array = ["is less than", "is bigger than"];
var sentenceArray = [];
for(var i in array){
    var s = sentence.split(array[i]);
    if(s[1]){
        sentenceArray.push(s[0].trim());
        sentenceArray.push(array[i]);
        sentenceArray.push(s[1].trim());
        break; // in case there are more than one unique delimiter in the array
    }
}

console.log(sentenceArray);

输出：

 ["1", "is less than", "2"]

Answer 3

将它们拆分为数字

var sentence = "1 is less than 2";
var sentenceArray  = sentence.split(/(\d+)/g).map(function(a){return a.trim()}).filter(function(a){return a;});
document.body.innerHTML = JSON.stringify(sentenceArray);

除了KeyWords之外，用空格分割

3 个答案: