Question

任何人都可以帮助我将3个广播播放器与html代码分开，并防止3个广播播放器变成3个相同的东西而不是3个不同的播放器。我可以在他们之间放什么代码？

例如，

如果你理解我的意思，所有3个电台播放器都会成为最后一个收音机。

 <script >(function (win, doc, script, source, objectName) { (win.RadionomyPlayerObject = win.RadionomyPlayerObject || []).push(objectName); win[objectName] = win[objectName] || function (k, v) { (win[objectName].parameters = win[objectName].parameters || { src: source, version: '1.1' })[k] = v; }; var js, rjs = doc.getElementsByTagName(script)[0]; js = doc.createElement(script); js.async = 1; js.src = source; rjs.parentNode.insertBefore(js, rjs); }(window, document, 'script', 'https://www.radionomy.com/js/radionomy.player.js', 'radplayer'));
radplayer('url', 'yowlandurbanradio');
radplayer('type', 'mobile');
radplayer('autoplay', '0');   
radplayer('volume', '50');
radplayer('color1', '#000000');
radplayer('color2', '#ffffff');
</script>
   <div class="radionomy-player"></div>



<script>(function (win, doc, script, source, objectName) { (win.RadionomyPlayerObject = win.RadionomyPlayerObject || []).push(objectName); win[objectName] = win[objectName] || function (k, v) { (win[objectName].parameters = win[objectName].parameters || { src: source, version: '1.1' })[k] = v; }; var js, rjs = doc.getElementsByTagName(script)[0]; js = doc.createElement(script); js.async = 1; js.src = source; rjs.parentNode.insertBefore(js, rjs); }(window, document, 'script', 'https://www.radionomy.com/js/radionomy.player.js', 'radplayer'));
radplayer('url', 'yowlandelectroradio');
radplayer('type', 'mobile');
radplayer('autoplay', '1');
radplayer('volume', '50');
radplayer('color1', '#000000');
radplayer('color2', '#ffffff');
</script>
  <div class="radionomy-player"></div>



<script>(function (win, doc, script, source, objectName) { (win.RadionomyPlayerObject = win.RadionomyPlayerObject || []).push(objectName); win[objectName] = win[objectName] || function (k, v) { (win[objectName].parameters = win[objectName].parameters || { src: source, version: '1.1' })[k] = v; }; var js, rjs = doc.getElementsByTagName(script)[0]; js = doc.createElement(script); js.async = 1; js.src = source; rjs.parentNode.insertBefore(js, rjs); }(window, document, 'script', 'https://www.radionomy.com/js/radionomy.player.js', 'radplayer'));
radplayer('url', 'yowlandjammakerradio');
radplayer('type', 'mobile');
radplayer('autoplay', '0');
radplayer('volume', '50');
radplayer('color1', '#000000');
radplayer('color2', '#ffffff');
</script>
  <div class="radionomy-player"></div>

Answer 1

首先不要使用类。使用ID使每个玩家都独一无二。第二件事：每次初始化新播放器时都不需要加载脚本。所以，这条线只需要一次：

<script>(function (win, doc, script, source, objectName) { (win.RadionomyPlayerObject = win.RadionomyPlayerObject || []).push(objectName); win[objectName] = win[objectName] || function (k, v) { (win[objectName].parameters = win[objectName].parameters || { src: source, version: '1.1' })[k] = v; }; var js, rjs = doc.getElementsByTagName(script)[0]; js = doc.createElement(script); js.async = 1; js.src = source; rjs.parentNode.insertBefore(js, rjs); }(window, document, 'script', 'https://www.radionomy.com/js/radionomy.player.js', 'radplayer'));</script>

函数radplayer(...)似乎已加载到radionomy脚本中，稍后将使用从脚本创建的iframe进行解析。

我实际上无法说出如何给每个玩家提供id（在JavaScript部分中）。但是如何做到这一点也应该记录在那里的开发者网站上。

分开玩家并防止重复

1 个答案: