Question

您好我有一个上传文件的简单表单，我想使用$ POST获取id值并放入数据库但我的代码不正确。这是我的代码。我只是想问一下我是否正确地传递和获取$ POST？感谢

echo "<form action='process.php' method='post' enctype='multipart/form-data' id='uploadfile'>";
 	echo "<input type='hidden' name='MAX_FILE_SIZE' value='100000' />";
	echo "<select name='selectedValue'>";
	echo '<option selected="selected">' .'Choose a User'. '</option>';
 	foreach ($registeredUsers as $key => $value) {
 		$registered = JFactory::getUser($value);
		echo '<option name="id" value="'.$registered->id.'">'.$registered->name.'</option>';

 	}
 	echo "</select>";
 	echo "Choose a file to Upload:";
 	echo "<input name='uploadedfile' type='file' /> <br/>";
 	echo '<input type="submit" name="submit" value="Upload">';
 	echo "</form>";

这是process.php文件。

if(isset($_POST['selectedValue']))
        {
            $selectedValue = $_POST['id'];

            $db = JFactory::getDbo();
            $query = $db->getQuery(true);

            $query = "INSERT INTO sample_table ('user_id') VALUES ('$_POST[id]')"

            $db->setQuery($query);
            $result = $db->execute();
        }

Answer 1

echo "<form action='process.php' method='post' enctype='multipart/form-data' id='uploadfile'>";
echo "<input type='hidden' name='MAX_FILE_SIZE' value='100000' />";
echo "<select name='id'>";
echo '<option selected="selected">' .'Choose a User'. '</option>';
foreach ($registeredUsers as $key => $value) {
    $registered = JFactory::getUser($value);
    echo '<option value="'.$registered->id.'">'.$registered->name.'</option>';

}
echo "</select>";
echo "Choose a file to Upload:";
echo "<input name='uploadedfile' type='file' /> <br/>";
echo '<input type="submit" name="submit" value="Upload">';
echo "</form>";

process.php

if(isset($_POST['id']))
{
    $selectedValue = $_POST['id'];

    $db = JFactory::getDbo();
    $query = $db->getQuery(true);

    $query = "INSERT INTO sample_table ('user_id') VALUES ('$selectedValue')";

    $db->setQuery($query);
    $result = $db->execute();
}

好。因此，您遇到了一些问题，您已经设置了＆＃34; name＆＃34;关于选项，这是错误的，你必须在。上设置其次，你在$ query的最后错过了一个分号最后，我已经检查了是否已从下拉列表中选择了一个值，并将selectedValue设置为该值，并在查询中使用该值。

如何获取$ POST数据并放入数据库

1 个答案: