Question

嗨我想成功登录然后调用我的成功函数，否则调用错误函数

在此处查看代码

<div class="container">
<div class="login-container">
    <div class="avatar"><img src="@Url.Content("~/Content/images/download.jpeg")" style="max-width:95%;" /></div>
    <div class="form-box">
        @using (Html.BeginForm())
        {
            <div class="input-group">
                <span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
                @Html.TextBoxFor(m => m.UserId, new { @class = "form-control", @id="userid", @placeholder = "Username", @required = "required", @maxlength = "20" })
            </div>
            <div class="input-group">
                <span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
                @Html.PasswordFor(m => m.Password, new { @class = "form-control", @id = "userpass", @placeholder = "Password", @required = "required", @maxlength = "20" })
            </div>
            <button class="btn btn-info btn-block login" type="submit" id="login-btn"><i class="glyphicon glyphicon-log-in"></i>&nbsp;&nbsp;&nbsp;Login</button>
        }
    </div>
</div>

ajax代码：

<script>
$(document).ready(function () {
    $('#login-btn').click(function () {
        var dataObject = {
            Id: $("#userid").val(),
            Password: $("#userpass").val()
        };
        $.ajax({
            url: '@Url.Action("Login","Account")',
            type: "POST",
            data: dataObject,
            dataType: "json",
            success: function (data) {

                if (data.toString() == "login") {
                    toastr['success']("Login Successfully");
                }
                else if (data.toString() == "error") {
                    toastr['error']("Id or Password is incorrect");
                }
            },
            error: function () {
                toastr['error']("Hello");
            }
        });

    });
});

控制器代码：

[HttpPost]
    public ActionResult Login(LoginMaster model)
    {
        string message = "";
        if (ModelState.IsValid)
        {
            try
            {
                var user = from emp in db.LoginMasters
                           where emp.UserId == model.UserId && emp.Password == model.Password
                           select emp;

                var rol = user.FirstOrDefault();
                if (rol != null)
                {
                    var realrol = rol.Role;
                    if (realrol == "admin")
                    {
                        message = "login";
                        return RedirectToAction("Index", "Home");
                    }
                    else if (realrol == "user")
                    {
                        Session["userid"] = rol.UserId;
                        message = "login";
                        return RedirectToAction("User", "Home");
                    }
                }
                else
                {
                    message = "error";
                }
            }
            catch (Exception ex)
            {
                ViewBag.cath = ex.Message;
            }

        }
        else
        {
            message = "error";
        }
        if (Request.IsAjaxRequest())
        {
            return new JsonResult { Data = message, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
        }

        return View();

我希望当我们成功登录时，请致电此

toastr['success']("Login Successfully");

当登录失败时，请致电

toastr['error']("Id or Password is incorrect");

请解决这个问题。提前谢谢！

Answer 1

假设您的控制器代码命中了返回json的部分，那么您可以通过.Data访问它：

success: function (data) {

            if (data.Data == "login") {
                toastr['success']("Login Successfully");
            }
            else if (data.Data == "error") {
                toastr['error']("Id or Password is incorrect");
            }
        }

您可以在代码中设置.Data属性：

new JsonResult { Data = message ...

并且成功调用的问题在于它正在测试整个json对象，不是 .Data属性。

data.toString() == "login"

Answer 2

不，先生，我们的问题是我们的行动，我们可以把生命中的生命点放在我们这一点首先执行的序列中

try
        {
            var user = from emp in db.LoginMasters
                       where emp.UserId == model.UserId && emp.Password == model.Password
                       select emp;

            var rol = user.FirstOrDefault();
            if (rol != null)
            {
                var realrol = rol.Role;
                if (realrol == "admin")
                {
                    message = "login";
                    return RedirectToAction("Index", "Home");
                }
                else if (realrol == "user")
                {
                    Session["userid"] = rol.UserId;
                    message = "login";
                    return RedirectToAction("User", "Home");
                }
            }
            else
            {
                message = "error";
            }
        }
        catch (Exception ex)
        {
            ViewBag.cath = ex.Message;
        }

然后执行此部分

<HorizontalScrollView
    android:fillViewport="true"
    android:id="@+id/product_hsv"
    android:layout_height="wrap_content"
    android:layout_width="match_parent"
    android:measureAllChildren="false"
    android:scrollbars="none">

    <LinearLayout
        android:id="@+id/product_container_layout"
        android:layout_height="match_parent"
        android:layout_width="match_parent"
        android:orientation="horizontal" />
</HorizontalScrollView>

所以问题是我们无法在消息变量中设置正确的字符串，所以首先你可以在js小提琴中制作一个样本，然后提供链接

Answer 3

正如您在脚本中使用此代码一样。：

var dataObject = {
            Id: $("#userid").val(),
            Password: $("#userpass").val()
        };

如果您的LoginMaster模型包含Id＆amp; Password它会显示数据。如果您有UserId＆amp; Password然后您必须在脚本中更改代码，如下所示。

 var dataObject = {
                UserId: $("#userid").val(),
                Password: $("#userpass").val()
            };

简而言之，将Id替换为UserId。

如何在mvc4中将数据从Action传递到Ajax成功函数？

3 个答案: