我与Codehaus Jackson的用户有问题。我有一个具有下一个属性和mapper声明的对象:
if(angular.isNumber($scope.Nuser.centerCode)){
alert('Center Code is a number');
}else {
alert('Center Code is not a number');
}
从另一个类使用:
public class AuthenticatedPrincipal implements Serializable, Principal {
@JsonIgnore
private final static ObjectMapper mapper = new ObjectMapper().enable(DeserializationConfig.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY).enableDefaultTyping(ObjectMapper.DefaultTyping.NON_FINAL)
.setSerializationInclusion(JsonSerialize.Inclusion.NON_NULL).setVisibility(JsonMethod.FIELD, JsonAutoDetect.Visibility.ANY);
private String name;
private Collection<String> roles;
private Collection<String> groups;
private boolean adminPrincipal;
...
@JsonIgnore
public String serialize() {
try {
return mapper.writeValueAsString(this);
} catch (IOException e) {
throw new RuntimeException("Unable to serialize Principal:" + toString(), e);
}
}
@JsonIgnore
public static AuthenticatedPrincipal deserialize(String json) {
try {
return mapper.readValue(json, AuthenticatedPrincipal.class);
} catch (IOException e) {
throw new RuntimeException("Unable to serialize Principal:" + json, e);
}
}
}
当我执行生成如下字符串的功能时:
public class AuthRequest {
@Transient
private AuthenticatedPrincipal principal;
@PreUpdate
@PrePersist
public void encodePrincipal() {
if (principal != null) {
this.encodedPrincipal = principal.serialize();
}
}
@PostLoad
@PostPersist
@PostUpdate
public void decodePrincipal() {
if (StringUtils.isNotBlank(encodedPrincipal)) {
this.principal = AuthenticatedPrincipal.deserialize(encodedPrincipal);
}
}
}
当方法AuthenticatedPrincipal.deserialize(encodedPrincipal);被称为解析Json参数,但该方法失败并出现此错误:
Principal:{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}
任何人都可以帮助我吗?
答案 0 :(得分:1)
Principal:{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}
无效的JSON。它需要看起来像这样
{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}
(开始时没有Principal:
)