Question

我有来自表

的以下样本数据

Id      Dsc
500001  INSURED
500001  THIRD PARTY
500001  THIRD PARTY
500001  THIRD PARTY
500002  INSURED
500002  THIRD PARTY
500003  INSURED
500004  BROKER
500005  CLAIMANT

我希望提取那些Dsc既不是“被保险人”的ID。也不是经纪人。由于两列都有重复数据，因此我设计了以下查询..

Select Id from table1 where Dsc not in ('Insured', 'Broker')
Except
Select Id from table1 where Dsc in ('Insured', 'Broker')

有没有其他方法可以做到这一点？

Answer 1

SELECT id FROM table1 GROUP BY id 
HAVING SUM(CASE WHEN Dsc='Insured' THEN 1 ELSE 0 END)=0
AND SUM(CASE WHEN Dsc='Broker' THEN 1 ELSE 0 END)=0

Answer 2

您可以将查询编写为：

SELECT Id FROM (
SELECT Id , SUM(CASE WHEN Dsc IN ('INSURED','BROKER') THEN 1 ELSE 0 END ) AS Condition
FROM @Test
GROUP BY Id
) T 
WHERE Condition = 0

DEMO

Answer 3

使用子查询：

Select id,dsc from (select id,dsc from table1 group by id, dsc) 
where dsc not in('Insured', 'Broker')

Answer 4

使用此代码停止重复列

Select distinct *from table1

在mysql中过滤一个组

4 个答案: