通过简单的Java“选择你自己的冒险”文本游戏

Question

我是Java和编码的新手。我已经开始通过these tutorials取得了巨大的成功，直到我到达this one。我知道在我的代码中我还没有进入“楼上”的选项，因为我想确保“厨房”选项首先正常工作。

代码编译得很好，但是当我在cmd行中运行它时，我可以选择进入“厨房”的第一个选项，但是当我选择查看“食品室”时，它需要2厘米线“食品储藏室“执行实际调查。

此外，如果我在查看“食品室”后选择“逃跑”选项，则不会使用“逃跑”选项打印文本。

很抱歉，如果有更简单的方法可以做到这一点，但我还没有学到它们。

感谢您的帮助！

import java.util.Scanner;

public class Adventure1
{
public static void main( String[] args ){
    Scanner keyboard = new Scanner(System.in);

String Go, Look, Pantry, Eat;

System.out.println( " WELCOME TO MY TINY ADVENTURE");
System.out.println("  ");
System.out.println( " You are in a creepy house! Would you like to go 'upstairs' or into the 'kitchen'? ");
System.out.print( "> ");
Go = keyboard.next();

if (Go.equalsIgnoreCase("kitchen"))
{System.out.println("There is a long countertop with dirty dishes everywhere. Off to one side there is, as you'd expect, a refrigerator. You may open the 'refrigerator' or look in the 'pantry'. ");}
System.out.print(">  ");
Look = keyboard.next();


    if (Look.equalsIgnoreCase( "refrigerator" ))
{System.out.println("Inside the refrigerator you see food and stuff. It looks pretty nasty. Would you like to eat some of the food, 'Yes' or 'No'?");}
System.out.print(">  ");
Eat = keyboard.next();

        if (Eat.equalsIgnoreCase("Yes"))
    {System.out.println("  ");
    System.out.println("You live!");}

        else if (Eat.equalsIgnoreCase("No"))
    {System.out.println("  ");
    System.out.println("You die of starvation!");}



else if (Look.equalsIgnoreCase( "pantry" ))
{System.out.println("There is a killer inside. Do you want to 'fight' them, or 'run away'?");}
System.out.print(">  ");
Pantry = keyboard.next();

        if (Pantry.equalsIgnoreCase("fight"))
    {System.out.println("  ");
    System.out.println("You're weak and die");}

        else if(Pantry.equalsIgnoreCase("run away"))
    {System.out.println("  ");
    System.out.println("You died because your too slow & can't run");}

}

    }

Answer 1

查看本节的逻辑......

if (Go.equalsIgnoreCase("kitchen")) {
    System.out.println("There is a long countertop with dirty dishes everywhere. Off to one side there is, as you'd expect, a refrigerator. You may open the 'refrigerator' or look in the 'pantry'. ");
}
System.out.print(">  ");
Look = keyboard.next();

if (Look.equalsIgnoreCase("refrigerator")) {
    System.out.println("Inside the refrigerator you see food and stuff. It looks pretty nasty. Would you like to eat some of the food, 'Yes' or 'No'?");
}
System.out.print(">  ");
Eat = keyboard.next();

如果用户进入“厨房”，则会提示他们refrigerator或pantry，如果他们输入pantry，您会直接进入空提示，实际上并不是处理了用户可能输入refrigerator

之外的其他内容的可能性

您的整个逻辑链都被打破了，您不是将这些部分分成单独的逻辑块来处理当前的情况。

例如，像......

Scanner keyboard = new Scanner(System.in);

String Go, Look, Pantry, Eat;

System.out.println(" WELCOME TO MY TINY ADVENTURE");
System.out.println("  ");
System.out.println(" You are in a creepy house! Would you like to go 'upstairs' or into the 'kitchen'? ");
System.out.print("> ");
Go = keyboard.next();

if (Go.equalsIgnoreCase("kitchen")) {
    System.out.println("There is a long countertop with dirty dishes everywhere. Off to one side there is, as you'd expect, a refrigerator. You may open the 'refrigerator' or look in the 'pantry'. ");
    System.out.print(">  ");
    Look = keyboard.next();

    if (Look.equalsIgnoreCase("refrigerator")) {
        System.out.println("Inside the refrigerator you see food and stuff. It looks pretty nasty. Would you like to eat some of the food, 'Yes' or 'No'?");
        System.out.print(">  ");
        Eat = keyboard.next();

        if (Eat.equalsIgnoreCase("Yes")) {
            System.out.println("  ");
            System.out.println("You live!");
        } else if (Eat.equalsIgnoreCase("No")) {
            System.out.println("  ");
            System.out.println("You die of starvation!");
        }
    } else if (Look.equalsIgnoreCase("pantry")) {
        System.out.println("There is a killer inside. Do you want to 'fight' them, or 'run away'?");
        System.out.print(">  ");
        Pantry = keyboard.next();

        if (Pantry.equalsIgnoreCase("fight")) {
            System.out.println("  ");
            System.out.println("You're weak and die");
        } else if (Pantry.equalsIgnoreCase("run away")) {
            System.out.println("  ");
            System.out.println("You died because your too slow & can't run");
        }
    }
}

会将每个逻辑块分组到它自己的组中。这将使您能够实际使用方法来进一步隔离逻辑。

你必须面对的下一个问题是当他们没有进入你期望的时候会怎样做

您将面临的另一个问题是Scanner#next将返回下一项工作，因此run away之类的内容将无效。相反，您可以考虑使用Scanner#nextLine代替

Answer 2

你的逻辑关闭了。看看食品储藏室的实际位置。

import java.util.Scanner;

public class Adventure1 {
    public static void main(String[] args) {
    Scanner keyboard = new Scanner(System.in);

    String Go, Look, Pantry, Eat;

    System.out.println(" WELCOME TO MY TINY ADVENTURE");
    System.out.println("  ");
    System.out
        .println(" You are in a creepy house! Would you like to go 'upstairs' or into the 'kitchen'? ");
    System.out.print("> ");
    Go = keyboard.next();

    if (Go.equalsIgnoreCase("kitchen")) {
        System.out
            .println("There is a long countertop with dirty dishes everywhere. Off to one side there is, as you'd expect, a refrigerator. You may open the 'refrigerator' or look in the 'pantry'. ");
    }
    System.out.print(">  ");
    Look = keyboard.next();

    if (Look.equalsIgnoreCase("refrigerator")) {
        System.out
            .println("Inside the refrigerator you see food and stuff. It looks pretty nasty. Would you like to eat some of the food, 'Yes' or 'No'?");
    } else if (Look.equalsIgnoreCase("pantry")) {
        System.out
            .println("There is a killer inside. Do you want to 'fight' them, or 'run away'?");
        Pantry = keyboard.next();

        if (Pantry.equalsIgnoreCase("fight")) {
        System.out.println("  ");
        System.out.println("You're weak and die");
        }

        else if (Pantry.equalsIgnoreCase("run away")) {
        System.out.println("  ");
        System.out
            .println("You died because your too slow & can't run");
        }
    }
    System.out.print(">  ");
    Eat = keyboard.next();

    if (Eat.equalsIgnoreCase("Yes")) {
        System.out.println("  ");
        System.out.println("You live!");
    }

    else if (Eat.equalsIgnoreCase("No")) {
        System.out.println("  ");
        System.out.println("You die of starvation!");
    }
    System.out.print(">  ");

    }

}