Question

我有一个问题，我如何合并文档（Doc1，Doc2和Doc3）的节点，以获得漂亮的3个开始模式。

for index, row in import_ds.iterrows():
     ind = ind+1
     graph.cypher.execute("MERGE (Document:Document"+str(fnum)+" {Document:\"Doc"+str(fnum)+"\"})")
     graph.cypher.execute("MERGE (Type:Type {Type:\""+str(row['type'])+"\"})<-[:HAS_TYPE]-(Word:Word {Word:\""+str(row['token_low'])+"\"})-[:IS_IN]->(Document:Document"+str(fnum)+" {Document:\"Doc"+str(fnum)+"\"})")

(WordType)<-[:HAS_TYPE]-(Word)-[:IS_IN]->(Document) http://www.yottalabs.co.uk/ss.png
[code output - Neo4j browser][1]

Answer 1

你应该使用参数，而不是字符串替换
merge尝试查找整个路径，如果不是，则创建整个路径

通常先将节点合并到rels：

MERGE (type:Type {Type: {type}})
MERGE (word:Word {Word:{token_low}})
MERGE (document:Document {Document:{doc}})
MERGE (type)<-[:HAS_TYPE]-(word)
MERGE (word)-[:IS_IN]->(document)

合并文档节点

MERGE (document:Document {Document:{doc}})
SET document.foo = {new_data}.foo, document.bar = {param_bar}

Neo4j将节点与关系合并

1 个答案:

合并文档节点