在我目前的Silex项目中,我希望通过Oauth和基本登录来实现登录。对于OAuth,我使用的是Silex扩展(https://github.com/gigablah/silex-oauth)。不幸的是,现在我在集成基本登录时遇到了问题。 我的想法是我必须创建一个自定义用户提供程序,它通过DB提供OAuth和密码,但我不知道如何实现它。
此时,我有一个非常丑陋的两个用户提供商的混合物。对我来说,这是逻辑,但它不会起作用。我想我不在赛道上了,所以如果你能给我一些提示,那就太好了 - 我现在试了几天......
我的用户提供商:
<?php
namespace Core;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\User;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Doctrine\DBAL\Connection;
class UserProvider implements UserProviderInterface
{
private $conn;
private $oauth;
public function __construct($oauth = null)
{
global $app;
if($oauth) { $this->oauth = $oauth; }
$this->conn = $app['db'];
}
/*public function loadAllUsers()
{
$users = $this->conn->executeQuery('SELECT * FROM users')->fetchAll();
$users_object = array();
foreach ($users as $user) {
if (!empty($user['username'])) {
$users_object[$user['username']] = array($user['password'], $user['firstname'], $user['lastname'], explode(',', $user['roles']));
}
}
$oauth = (array)$this->oauth;
print_r($oauth->users);
if (count($oauth['users']) > 0 ) {
print_r($this->oauth);
}
if ($this->oauth) {
if (count($oauth['users'])) {
return $this->oauth;
} else {
} return $users_object;
} else {
return $users_object;
}
}*/
public function loadUserByOAuthCredentials($token)
{
return $this->oauth->loadUserByOAuthCredentials($token);
}
public function loadUserByUsername($username)
{
if ($this->oauth->loadUserByUsername($username)) {
return $this->oauth->loadUserByUsername($username);
} else {
$stmt = $this->conn->executeQuery('SELECT * FROM users WHERE username = ?', array(strtolower($username)));
if (!$user = $stmt->fetch()) {
throw new UsernameNotFoundException(sprintf('Username "%s" does not exist.', $username));
}
return new User($user['username'], $user['password'], explode(',', $user['roles']), true, true, true, true);
}
}
public function refreshUser(UserInterface $user)
{
if (!$user instanceof User) {
throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', get_class($user)));
}
return $this->loadUserByUsername($user->getUsername());
}
public function supportsClass($class)
{
return $class === 'Symfony\Component\Security\Core\User\User';
}
}
提前感谢您,如果您需要更多信息,请告诉我。 索拉斯