Question

在一个类中，我得到一个包含事实的字符串，如下所示：

public class FactBook {
    public String[] mFacts = {"a", "b", "c"};
    ....

现在我有一个像这样的随机发生器：

public String getFact() {
    String fact = "";

    Random randomGenerator = new Random();  

    int randomNumber = randomGenerator.nextInt(mFacts.length);

    fact = mFacts[randomNumber];

    return fact;
}

活动类中的randomButton是这样的：

final TextView factLabel = (TextView) findViewById(R.id.factTextView);
final Button showFactButton = (Button) findViewById(R.id.showFactButton);
final RelativeLayout relativeLayout = (RelativeLayout) findViewById(R.id.relativeLayout);
final MediaPlayer mMediaPlayer = MediaPlayer.create(getApplicationContext(), R.raw.button);

View.OnClickListener listener = new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        mMediaPlayer.start();

        String fact = mFactBook.getFact();
        //Update the Label with our dynamic fact
        factLabel.setText(fact);

        int color = mColorWheel.getColor();
        relativeLayout.setBackgroundColor(color);
        showFactButton.setTextColor(color);
    }
};
showFactButton.setOnClickListener(listener);

现在我想创建一个逐步遍历数组的按钮（如 nextButton 和 previousButton ）。但是我被卡住了。有人有什么想法吗？

Answer 1

创建接受字符串数组并对其进行操作的类，实现非常基础，视为poc;）

public class Facts
{
   private String[] mFacts;
   private int current = 0;
   public Facts( String[] mFacts )
   {
       this.mFacts = mFacts;
   }

   public boolean hasPrevious()
   {
      return current >= 0;
   }

   public boolean hasNext()
   {
       return current < mFacts.length;
   }

   public String next()
   {
       if( !hasNext() )
       {
            return null;
       }
       String v = mFacts[ current ];
       current++;
       return v;
   }

   public String previous()
   {
       if( !hasPrevious() )
       {
            return null;
       }
       String v = mFacts[ current ];
       current--;
       return v;
   }

   public String random()
   {
        Random randomGenerator = new Random(); 
        int randomNumber = randomGenerator.nextInt(mFacts.length);
        return mFacts[randomNumber];
   }
}

<强>更新代码中的某处Facts facts = new Facts（String [] array）;虽然我不熟悉android，但我在你的消息来源中看到按钮是在另一个地方创建的（可能是某些gui工具）。在每次单击按钮时，它将遍历数组直到结束。要动态创建按钮（从文档中读取），您可以使用它。

public class ButtonCreator
{
    private Facts facts;
    public ButtonCreator( Facts facts )
    {
        this.facts = facts;
    }

    public boolean canCreateNextButton() { return facts.hasNext(); }
    public boolean canCreatePreviousButton() { return facts.hasPrevious(); }
    public Button createNextButton( Context context )
    {
        Button button = new Button( context );
        button.setText( facts.next() );
        return button;
    }
    public Button createPreviousButton( Context context )
    {
        Button button = new Button( context );
        button.setText( facts.previous() );
        return button;
    }
}

然后在创建后设置适当的侦听器，如粘贴代码

然后在表单

的初始化期间

String[] arr = {"AAA","BBBB","CCC"};
Facts f = new Facts( array );
ButtonCreator creator = new ButtonCreator( f );

while( creator.canCreateNextButton() )
{
    Button button = creator.nextButton( //view context here// );
    button.setListener( //listener here// );    
}

如何获取String Array中的下一个按钮

1 个答案: