Question

$arr = array('0:16:0', '25:12:5', '0:0:10', '0:5:0');

// converting all the times to seconds
$t_seconds = 0;
foreach ($arr as $v) {
    sscanf($v, "%d:%d:%d", $hours, $minutes, $seconds);
    $t_seconds += $hours * 3600 + $minutes * 60 + $seconds;
}

// condition if seconds calculated are negative
$sign = ($t_seconds < 0 ? '-' : '');
$t_seconds = abs($t_seconds);

// converting seconds, taking care of wrong minutes/seconds formats like 02:63:65
$hours = floor($t_seconds / 3600);
$minutes = floor(($t_seconds / 60) % 60);
$seconds = $t_seconds % 60;

// final format
$sum = $sign . sprintf("%02d:%02d:%02d", $hours, $minutes, $seconds);

输出：

25:33:15

Answer 1

输入的值无效。使用PreparedStatement设置查询中的值。在sql中使用应插入值的列名。主键默认在MySQL中自动生成，因此您无需使用它。最后，您也不需要指定;。执行语句时，它会自动添加结束字符。

//SQL Query to insert user input
String sql = "insert into tab(name, age) values(?,?)";  
Statement st = con.prepareStatement(sql);

st.setString(1, name);
st.setInt(2, age);

//Execute INSERT
st.executeUpdate();

这个jdbc程序中的错误是什么

1 个答案: