Question

我可以使用相机拍摄照片或从画廊拍摄并使用此代码在ImageView中显示。我现在需要做的是使用该图片并将其上传到Parse。我一直在谷歌上搜索这个，我还没有找到正确的方法来做到这一点。有人可以帮我这个吗？是否可以从ImageView上传图像？谢谢。

protected Button mFromCamera;
protected Button mFromGallery;
protected ImageView mImageView;

private static final int CAMERA_REQUEST = 1888;
private static final int SELECT_PHOTO = 100;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);


//Initialize ImageView
mImageView = (ImageView) findViewById(R.id.ImgPrev);
//Initialize Camera
mFromCamera = (Button) findViewById(R.id.FromCamera);

//use camera
mFromCamera.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
        startActivityForResult(cameraIntent, CAMERA_REQUEST);
    } //use camera end

});

//initialize button
mFromGallery = (Button) findViewById(R.id.FromGallery);

//pick a photo
mFromGallery.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View arg0) {
        Intent photoPickerIntent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
        photoPickerIntent.setType("image/*");
        startActivityForResult(photoPickerIntent, SELECT_PHOTO);
    }
});//pick a photo end
}



//previewing Image
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
    //from the gallery
    case SELECT_PHOTO:
        if (requestCode == SELECT_PHOTO && resultCode == RESULT_OK && null!= data) {
            Uri selectedImage = data.getData();
            String[] filePathColumn = { MediaStore.Images.Media.DATA };

            Cursor cursor = getContentResolver().query(selectedImage,
                    filePathColumn, null, null, null);
            cursor.moveToFirst();

            int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
            String picturePath = cursor.getString(columnIndex);
            cursor.close();

            mImageView.setImageBitmap(BitmapFactory.decodeFile(picturePath));
        }
        break;
    //from the camera
    case CAMERA_REQUEST:
        if (requestCode == CAMERA_REQUEST && resultCode == RESULT_OK) {
            Bitmap photo = (Bitmap) data.getExtras().get("data");
            mImageView.setImageBitmap(photo);
        }
        break;
}
}//Preview Image End

Answer 1

阅读你的答案：

我已经按照您之前的代码进行操作了。我能够上传图像进行解析。但我不知道如何将可绘制源切换为我的图像来自相机/图库或imageview。 - stanley santoso

到：

Abhishek Bansal

我知道您的问题不是解析您的图片吗？

试着回答你的问题：

我不知道如何将可绘制的源从相机/图库或图像视图切换为我的图像。

1 - R.drawable.androidbegin似乎是你的问题但事实是你已经在你的代码中解析了你的位图：

来自图库 - ＆gt;

mImageView.setImageBitmap(BitmapFactory.decodeFile(picturePath));

来自相机 - ＆gt;

Bitmap photo = (Bitmap) data.getExtras().get("data");

2 - 所以我建议在代码的开头声明一个Bitmap类型的变量

private Bitmap yourbitmap;

3 - 然后在您的代码中为图库和相机指定位图，并使用它来解析它。

...
yourbitmap = BitmapFactory.decodeFile(picturePath);
...
yourbitmap = (Bitmap) data.getExtras().get("data");
...

4 - 最后你可以这样使用你的位图：

//    Bitmap bitmap = BitmapFactory.decodeResource(getResources(),
//                            R.drawable.androidbegin);
    // Convert it to byte
                    ByteArrayOutputStream stream = new ByteArrayOutputStream();
                    // Compress image to lower quality scale 1 - 100
                    yourbitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
                    byte[] image = stream.toByteArray();
           ...

Answer 2

互联网上有很好的教程。基本上就是你需要做的事情

Bitmap bitmap = BitmapFactory.decodeResource(getResources(),
                        R.drawable.androidbegin);
                // Convert it to byte
                ByteArrayOutputStream stream = new ByteArrayOutputStream();
                // Compress image to lower quality scale 1 - 100
                bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
                byte[] image = stream.toByteArray();

                // Create the ParseFile
                ParseFile file = new ParseFile("androidbegin.png", image);
                // Upload the image into Parse Cloud
                file.saveInBackground();

                // Create a New Class called "ImageUpload" in Parse
                ParseObject imgupload = new ParseObject("ImageUpload");

                // Create a column named "ImageName" and set the string
                imgupload.put("ImageName", "AndroidBegin Logo");

                // Create a column named "ImageFile" and insert the image
                imgupload.put("ImageFile", file);

                // Create the class and the columns
                imgupload.saveInBackground();

来源：this tutorial

也会看到这个问题How to upload an image in parse server using parse api in android

Answer 3

点击here以获取AsyncHttpClient库并上传您的图片。上传图片是件好事。

public void uploadImage(Bitmap img_bit)
{
    AsyncHttpClient imgupload = new AsyncHttpClient();
    RequestParams params = new RequestParams();
        if (img_bit != null) {

            byte[] imagebyte;
            ByteArrayOutputStream bao = new ByteArrayOutputStream();
            img_bit.compress(Bitmap.CompressFormat.PNG, 100, bao);
            imagebyte = bao.toByteArray();
            params.put("image", new ByteArrayInputStream(imagebyte),   "test"+ System.currentTimeMillis() + ".png");
        }
        imgupload.post("url",params, new AsyncHttpResponseHandler() {

                            @Override
                            public void onSuccess(int arg0, Header[] arg1,
                                    byte[] arg2) {
                                System.out.println("Image Upload successfully");
                            }

                            @Override
                            public void onFailure(int arg0, Header[] arg1,
                                    byte[] arg2, Throwable arg3) {
                                System.out.println("faile the data");
                            }
                        });


     }

如何在Android中将图像上传到Parse？

3 个答案: