Question

我有三张桌子：

TimeSlot table having(TimeSlotId,TimeSlotStart,TimeSlotEnd,TimeSlotToken)
AppointmentSchedule having (ApptId,DoctorId,TimeSlot1Id,TimeSlot2Id,TimeSlot3Id)
Booking having (BookingId,DoctorId,PatientId,BookingDate,TimeSlotId)

TimeSlotToken是医生在他的TimeSlot中看到的患者人数 TimeSlot 1,2和3分别是上午，下午和晚上。

我需要找到TimeSlot未满的日子，即TimeSlot令牌少于该特定日期和该位置的总预订量。由于每位医生每天可能有多个时段，我遇到了麻烦。如果在特定日期填写了所有三个TimeSlots，请向我显示那些不可用的日期（我将在稍后使用）。并找到那些没有填补时间段的时间段和日期。

要查找不可用的日期，我正在尝试代码：

with total_token(token) as (
  select timeslottoken 
    from timeslot 
   where timeslotid=(select timeslot1id,timeslot2id,timeslot3id 
                       from appointmentbooking 
                      where doctor id=1001),
with token_as_day(bookingdate,token) as (
  select bookingdate,count(distinct bookingid) 
    from bookings 
   where doctor_id=1001 
   group by booking_date,timeslot_id)   
select token_as_day.bookingdate 
  from total_token,token_as_day
 where token_as_day.token'<'total_token.token;

但这不起作用。请帮忙！
P.S-列名称不区分大小写。我有更复杂的名字，我在这里简化，因此差异..

Answer 1

^{从评论到答案供参考 - 由于OP自己也达成了相同的解决方案。}

WITH
Total_Token (timeSlotStart, token) AS (
  SELECT
    timeSlotStart, timeSlotToken
  FROM TimeSlot
  WHERE
    timeSlotId IN (SELECT
                    timeSlot1Id
                  FROM AppointmentSchedule
                  WHERE doctorId = 1
                  UNION ALL
                  SELECT
                    timeSlot2Id
                  FROM AppointmentSchedule
                  WHERE doctorId = 1
                  UNION ALL
                  SELECT
                    timeSlot3Id
                  FROM AppointmentSchedule
                  WHERE doctorId = 1
                  )
),
Token_As_Day (bookingDate, token) AS (
  SELECT
    bookingDate, COUNT(DISTINCT bookingId)
   FROM Booking
   WHERE doctorId = 1
   GROUP BY bookingDate, timeSlotId
)
SELECT
  Token_As_Day.bookingDate
FROM Total_Token
JOIN Token_As_Day
  ON TRUNC(Total_Token.timeSlotStart) = TRUNC(Token_As_Day.bookingDate)
  AND Token_As_Day.token < Total_Token.token
;

查看实际操作：SQL Fiddle。

找出可供医生预约的日期和时段

1 个答案: