Question

我是一个菜鸟，我正在尝试区分两个查询输出。每个查询都会创建一个列表查询列表＆gt;查询B列表。此外，查询B输出是查询A的子集。

查询A：

SELECT first_name, last_name
FROM users
WHERE rating <> '6';

查询B：

SELECT DISTINCT first_name, last_name
FROM users
JOIN mp_positions
ON users.id=mp_positions.user_id
JOIN mps
ON mps.id=mp_positions.mp_id
WHERE mps.status_id = '5';

任何帮助都将不胜感激。

Answer 1

我会使用this因此

-- It returns rows from Query B which "doesn't exist in" Query A
SELECT DISTINCT first_name, last_name
FROM users
JOIN mp_positions
ON users.id=mp_positions.user_id
JOIN mps
ON mps.id=mp_positions.mp_id
WHERE mps.status_id = '5'

EXCEPT

SELECT first_name, last_name
FROM users
WHERE rating <> '6';

然后

var shape = new Shape();
shape.graphics.beginPath();
shape.graphics.circle(100, 100, 50);
shape.graphics.closePath();
shape.graphics.fillColor(Color.Red);
stage.addChild(shape);

Answer 2

虽然您可能想尝试这样的事情，但我并不完全确定您的牌桌结构：

SELECT first_name, last_name 
FROM users 
WHERE rating <> '6'
AND users.id
NOT IN (SELECT DISTINCT first_name, last_name 
             FROM users 
             JOIN mp_positions 
             ON users.id=mp_positions.user_id 
             JOIN mps ON mps.id=mp_positions.mp_id 
             WHERE mps.status_id = '5'
);

减去2个SQL查询的输出

2 个答案: