Question

我有import csv import os import subprocess def callGetDimmBatchFile(goodFile, badFile, logFile, batchFileName, ipAddress, userName, passWord): command ='{0} -i {1} -u {2} -p {3}'.format(batchFileName, ipAddress, userName, passWord) print(command) logFile.write(command + '\n') logFile.flush() p = subprocess.Popen(command) output = p.communicate() logFile.write('{0}'.format(output) + '\n') logFile.flush() goodFile = open('good.txt', 'w+') badFile = open('bad.txt', 'w+') logFile = open('log.txt', 'w+') batchFileName = 'getdimm.bat' pathToCsv = 'autorun-input.csv' print('Path to CSV is {0}'.format(pathToCsv)) counter = 0 with open(pathToCsv) as csvFile: reader = csv.reader(csvFile, delimiter=',') for row in reader: ipAddress = row[0] userName = row[1] passWord = row[2] counter += 1 print(counter) logFile.write('{0}'.format(counter) + '\n') logFile.flush() callGetDimmBatchFile(goodFile, badFile, logFile, batchFileName, ipAddress, userName, passWord) os.system("pause")，我想要BYTE bMins = 36;和bMin1 = 3;

没有长开关等可能吗？

我已经用bMin2 = 6;尝试了，但这很慢。

Answer 1

整数除法和模数帮助：

setTimeout(function(){
     $("audio").prop('muted', false);
}, 10000);

Answer 2

这是一个示范程序

#include <iostream>
#include <cstdlib>

int main() 
{
    typedef unsigned char BYTE;
    BYTE bMins = 36;
    BYTE bMin1, bMin2;

    auto d = std::div( bMins, 10 );
    bMin1 = d.quot;
    bMin2 = d.rem;

    std::cout << "bMin1 = " << ( int )bMin1 << ", bMin2 = " << ( int )bMin2 << std::endl; 
}

程序输出

bMin1 = 3, bMin2 = 6

Answer 3

另一种方法是转换为字符串并使用数字字符：

BYTE bMins = 36;
std::string s = std::to_string(bMins);
BYTE bMin1 = s[0] - '0';
BYTE bMin2 = s[1] - '0';

如何从数字中提取特定数字？

3 个答案: