Mysql ORDER BY COUNT（*）获取最旧的行

Question

你能帮帮我吗？我想

1）检查来自tb_pre_sale的id是否在列seler_0上不存在或者是否存在但至少重复2次

2）获取最老的

谢谢！

 SELECT DISTINCT seller_0 
 FROM tb_pre_sale 
 WHERE seller_0 !=? 
 GROUP BY id 
 ORDER BY COUNT(*) < ? DESC

Answer 1

 SELECT seller_0 
 FROM tb_pre_sale 
 WHERE seller_0 !=? 
 GROUP BY  seller_0 
 HAVING COUNT(*) < ? ORDER BY seller_0 DESC