我在wordpress中创建了自定义主题。 我想在自定义帖子模板中添加自定义分页,即INDEX.PHP
请您检查分页脚本中的错误。实际上我已经设置了4个帖子限制,并且在我的博客中有大约8个帖子..当点击2分页时,它不会移动到下一页...
shouldComponentUpdate
请帮忙:) 谢谢, Harshad Patil
答案 0 :(得分:2)
试试这个
$paged = ( get_query_var( 'paged' ) ) ? absint( get_query_var( 'paged' ) ) : 1;
// WP_Query arguments
$args = array (
'post_type' => 'YOUR_CUSTOM_POST_TYPE',
'posts_per_page' => '3',
'paged' => $paged
);
// The Query
$cquery = new WP_Query( $args );
while ( $cquery->have_posts() ) : $cquery->the_post();
echo $post->ID;
endwhile;
$big = 999999999; // need an unlikely integer
echo paginate_links( array(
'base' => str_replace( $big, '%#%', esc_url( get_pagenum_link( $big ) ) ),
'format' => '?paged=%#%',
'current' => max( 1, get_query_var('paged') ),
'total' => $cquery->max_num_pages
) );
答案 1 :(得分:1)
在" functions.php"中添加以下代码文件:
function custom_pagination($pages = '', $range = 2)
{
$showitems = ($range * 2)+1;
global $paged;
if(empty($paged)) $paged = 1;
if($pages == '')
{
global $wp_query;
$pages = $wp_query->max_num_pages;
if(!$pages)
{
$pages = 1;
}
}
if(1 != $pages)
{
echo "<div class='pagination'>";
if($paged > 2 && $paged > $range+1 && $showitems < $pages) echo "<a href='".get_pagenum_link(1)."'>«</a>";
if($paged > 1 && $showitems < $pages) echo "<a href='".get_pagenum_link($paged - 1)."'>‹</a>";
for ($i=1; $i <= $pages; $i++)
{
if (1 != $pages &&( !($i >= $paged+$range+1 || $i <= $paged-$range-1) || $pages <= $showitems ))
{
echo ($paged == $i)? "<span class='current'>".$i."</span>":"<a href='".get_pagenum_link($i)."' class='inactive' >".$i."</a>";
}
}
if ($paged < $pages && $showitems < $pages) echo "<a href='".get_pagenum_link($paged + 1)."'>›</a>";
if ($paged < $pages-1 && $paged+$range-1 < $pages && $showitems < $pages) echo "<a href='".get_pagenum_link($pages)."'>»</a>";
echo "</div>\n";
}
}
在你的&#34; index.php&#34; file add&#34; custom_pagination();&#34;在while循环之后。