Question

我尝试使用操作创建通知，但我无法将此行代码转换为Javascript：

Intent resultIntent = new Intent(this, ResultActivity.class);

来自https://developer.android.com/training/notify-user/build-notification.html

有人可以帮忙吗？或者有一个功能实例？感谢

Answer 1

有效！

var app = require('application');

var packageName = app.android.context.getPackageName();
var launchIntent = app.android.context.getPackageManager().getLaunchIntentForPackage(packageName);
var className = launchIntent.getComponent().getClassName();
var tns = className + '.class';

var intent = new android.content.Intent(app.android.context, eval(tns));

var pIntent = android.app.PendingIntent.getActivity(app.android.context, 0, intent, 0);

var resImg = app.android.context.getResources().getIdentifier('icon' , 'drawable', app.android.context.getPackageName());

var mBuilder = new android.support.v4.app.NotificationCompat.Builder(app.android.context);
mBuilder.setSmallIcon(resImg);
mBuilder.setContentTitle('My notification');
mBuilder.setContentText('Hello World!');
mBuilder.addAction(resImg, 'see', pIntent);

var mNotificationId = 001;
var sytemservice = app.android.context.getSystemService(android.content.Context.NOTIFICATION_SERVICE);
sytemservice.notify(mNotificationId, mBuilder.build());

使用模拟器android 4.2.2进行测试

Nativescript无法让android通知操作正常工作

1 个答案: