Question

我使用春季休息。

我想显示一个对象并保存它。

@RequestMapping(value = "/lodgers", method = RequestMethod.POST)
public LodgerInformation createLodger(@RequestBody @Valid final LodgerInformation lodgerDto) {
    return lodgerService.save(lodgerDto);
}

public class LodgerInformation {
    private long lodgerId;
    private String firstName;
    private String lastName;
    private List<IdentityCardDto> identityCardDtoList;
    ...
}



public class IdentityCardDto {
    private long identityCardId;
    private IdentityCardTypeDto identityCardTypeDto;
    private String value;
    ...
}

public class IdentityCardTypeDto {
    private long identityCardTypeId;
    private String identityCardType;
    private Date expiration;
    private boolean hasExpirationDate=false;
    ...
}

在HTML方面，我需要使用什么结构来命名？是否有一些库可以帮助进程为html组件赋值和反向

得到答案：

＆＃34; {＆＃34; timestamp＆＃34;：1436292452811，＆＃34; status＆＃34;：400，＆＃34;错误＆＃34;：＆＃34;错误请求＆＃34;，＆＃34; exception＆＃34;：＆＃34; org.springframework.http.converter.HttpMessageNotReadableException＆＃34;，＆＃34; message＆＃34;：＆＃34;无法读取文档：无法识别的令牌＆＃39; firstName＆＃39;：期待＆＃39; null＆＃39;，＆＃39; true＆＃39;，＆＃39; false＆＃39;或NaN \ n at [来源：java.io.PushbackInputStream@3f7cf4ca; line：1，column：11];嵌套异常是com.fasterxml.jackson.core.JsonParseException：无法识别的标记＆＃39; firstName＆＃39;：期待＆＃39; null＆＃39;，＆＃39; true＆＃39;，＆＃39; false＆＃ 39;或NaN \ n at [来源：java.io.PushbackInputStream@3f7cf4ca; line：1，column：11]＆＃34;，＆＃34; path＆＃34;：＆＃34; / lodgers＆＃34;}＆＃34;

Answer 1

此处需要发送的输入应采用以下格式

{
lodgerId : 1,
identityCardDtoList: [{
                        identityCardId: 11,
                        identityCardTypeDto:{
                            identityCardTypeId: 111,
                            identityCardType: "Node 1.1.1",
                            expiration: 12/12/2015,
                            hasExpirationDate: true
                            }
                       },{
                        identityCardId: 12,
                        identityCardTypeDto:{
                            identityCardTypeId: 112,
                            identityCardType: "Node 1.1.2",
                            expiration: 12/12/2015,
                            hasExpirationDate: true
                            }
                     }] 
}

请告诉我这是否是您正在寻找的

Answer 2

表单看起来像这样

 <form id="newPersonForm">
      <label for="nameInput">Name: </label>
      <input type="text" name="name" id="nameInput" />
      <br/>
       
      <label for="ageInput">Age: </label>
      <input type="text" name="age" id="ageInput" />
      <br/>
      <input type="submit" value="Save Person" /><br/><br/>
      <div id="personFormResponse" class="green"> </div>
    </form>

jquery调用代码看起来像这样

$(document).ready(function() {
// Save Person AJAX Form Submit
      $('#newPersonForm').submit(function(e) {
        // will pass the form data using the jQuery serialize function
        $.post('${pageContext.request.contextPath}/api/person', $(this).serialize(), function(response) {
          $('#personFormResponse').text(response);
        });
      });

    });

控制器代码

@Controller
@RequestMapping("api")
public class PersonController {

    PersonService personService;
// handles person form submit
@RequestMapping(value="person", method=RequestMethod.POST)
@ResponseBody
public String savePerson(@RequestBody Person person) {
    personService.save(person);
    return "Saved person: " + person.toString();
}

Person对象必须转换为JSON。由于Spring的HTTP消息转换器支持，您无需手动执行此转换。因为Jackson 2在类路径上，所以会自动选择Spring的MappingJackson2HttpMessageConverter将Greeting实例转换为JSON。发送到控制器的Person对象将由jquery映射，在@RequestBody

的帮助下创建Person对象

将值从服务器分配给html并保存

2 个答案: