我正在开发一个Android应用程序,它将使用java类HttpsURLConnection连接到网页,并使用JSoup解析HTML响应。问题是来自网站的HTML响应似乎是编码的。有关如何获取实际HTML的任何想法?
以下是我联系网站的代码:
private String GetPageContent(String url) throws Exception {
URL obj = new URL(url);
conn = (HttpsURLConnection) obj.openConnection();
// default is GET
conn.setRequestMethod("GET");
conn.setUseCaches(false);
// act like a browser
conn.setRequestProperty("User-Agent", USER_AGENT);
conn.setRequestProperty("Accept",
"text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8");
conn.setRequestProperty("Accept-Language", "en-US,en;q=0.8,en-GB;q=0.6");
conn.setRequestProperty("Accept-Encoding" , "gzip, deflate, sdch");
conn.setRequestProperty("Connection" , "keep-alive");
if (cookies != null) {
for (String cookie : this.cookies) {
conn.addRequestProperty("Cookie", cookie.split(";", 1)[0]);
}
}
int responseCode = conn.getResponseCode();
Log.v(TAG,"\nSending 'GET' request to URL : " + url);
Log.v(TAG,"Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// Get the response cookies
setCookies(conn.getHeaderFields().get("Set-Cookie"));
return response.toString();
}
回复的片段:
��������������]�r�6��۞�w@ՙ�NDQ�ﱥ|�siv�Kkw�m&�HH�M, Z��ff_c_o�d�@���9�l�6����� �_=w|����/A{��!W� LZ��������f]�=wc߽�2,˨�|�8x��~�}�x1�$Ib�Uq�7�j�X|;��K
编辑:HTML使用GZIP进行编码,如请求标头here中所示。
此问题的解决方案是使用GZIPInputStream类,如下所示:
BufferedReader in = new BufferedReader(new InputStreamReader(
new GZIPInputStream(conn.getInputStream())));
答案 0 :(得分:1)
根据请求返回的标头,我们可以得出结论,内容是使用gzip编码的。幸运的是,使用GZIPInputStream类可以轻松解码gzip编码流。
答案 1 :(得分:0)
不知道您尝试访问哪个网址,但是您是否尝试过设置字符集?
BufferedReader in = new BufferedReader(new InputStreamReader(
conn.getInputStream(), "UTF8"));