我知道有与whatsapp沟通的方案,如:
NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?text=Hello%2C%20World!"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
[[UIApplication sharedApplication] openURL: whatsappURL];
}
但是我找不到如何使用之前不存在的电话号码打开whatsapp。
这是一个“contatc us”页面,如果我只能打开whatsapp而无法预先填写电话号码,那就没用了。我需要与whatsapp联系......
我想做的是什么?
答案 0 :(得分:8)
预先填写的电话号码和文字
NSURL *whatsappURL = [NSURL URLWithString:@"https://api.whatsapp.com/send?phone=9530670491&text=hello"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
[[UIApplication sharedApplication] openURL: whatsappURL];
}
点击此处查看Swift
答案 1 :(得分:1)
答案 2 :(得分:1)
您可以在上面找到该whatsapp API的文档答案。根据我自己的试用添加更多的一点:
直接与特定联系人沟通,您需要该联系人。 ABID是保存联系人时系统自动生成的参数。因此,如果您的联系人中没有保存号码,那么您无法从应用程序中打开该号码。
我使用过一种解决方法。当您的应用程序首次加载到设备中时,会将联系我们号码保存到地址簿中。当数字保存成功后,您将在返回时获得ABID。您可以使用该ABID来调用该联系人的消息。
NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?abid=123&text=Hello%2C%20World!"];
答案 3 :(得分:1)
如果有人在寻找Swift版本
static func triggerWhats(_ vc:UIViewController){
let msg = "Hello! I have a question"
let urlWhats = "whatsapp://send?phone=+6599999999&text=\(msg)"
if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed){
if let whatsappURL = NSURL(string: urlString) {
if UIApplication.shared.canOpenURL(whatsappURL as URL) {
_ = UIApplication.shared.open(whatsappURL as URL, options: [:], completionHandler: nil)
} else {
// Cannot open whatsapp
ViewUtil().popAlertView(vc, title: "WhatsApp Support", message: "Please WhatsApp us at +65999999 if you have any questions", option: "Ok")
}
}
}
}
答案 4 :(得分:1)
Swift 3.0开放应用程序。
在 info.plist 文件中添加此行
<key>LSApplicationQueriesSchemes</key>
<array>
<string>whatsapp://</string>
</array>
func OpenWhatsApp(_ vc:UIViewController){
let msg = "" // here pass your message
let urlWhats = "https://api.whatsapp.com/send?phone=(Mobileno)&text=\(msg)" // Mobile number that include country code and without + sign .
if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed){
if let whatsappURL = URL(string: urlString) {
if UIApplication.shared.canOpenURL(whatsappURL) {
if #available(iOS 10.0, *) {
_ = UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)
} else {
// Fallback on earlier versions
UIApplication.shared.canOpenURL(whatsappURL)
}
} else {
// Cannot open whatsapp
AppUtilities.sharedInstance.showAlert(title: "WhatsApp Support", msg: "Your device is not support whats app")
}
}
}
}
答案 5 :(得分:0)
对于Swift 3.0或更高版本,这将打开数字的whatsapp聊天
数字示例:“ + 918798766554”
if let whatappURL = URL(string: "https://api.whatsapp.com/send?phone=\(number)&text=\(msg)"),
UIApplication.shared.canOpenURL(whatappURL)
{
if #available(iOS 10.0, *) {
UIApplication.shared.open(whatappURL, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(whatappURL)
}
}
答案 6 :(得分:0)
对于Swift 3.0或更高版本,这将打开数字的whatsapp聊天
数字示例:“ + 6599999999”
UIApplication.shared.open(URL(string: "https://wa.me/+6599999999")!)