Question

我在AngularJS控制器中定义了一个在初始化时调用的方法。我想用Jasmine（"jasmine-core": "^2.3.4", "karma": "^0.12.37"）测试它。我在互联网和StackOverflow问题上遵循一些教程，但我找不到正确的答案。请看一下这段代码：

Controller usersAddUserController：

(function () {
    'use strict';

    angular.module('app.users.addUser')
        .controller('usersAddUserController', ['$scope', 'usersAddUserService', function ($scope, usersAddUserService) {

            usersAddUserService.getCountryPhoneCodes().then(function (phoneCodes) {
                $scope.phoneCodes = phoneCodes;
            });

        }]);
}());

茉莉花测试：

(function () {

    'use strict';

    describe('usersAddUserControllerUnitTest', function () {
        var scope, deferred, objectUnderTest, mockedAddUserService;

        beforeEach(module('app'));

        beforeEach(inject(function ($rootScope, $q, $controller) {
            scope = $rootScope.$new();

            function emptyPromise() {
                deferred = $q.defer();
                return deferred.promise;
            }

            mockedAddUserService = {
                getCountryPhoneCodes: emptyPromise
            };

            objectUnderTest = $controller('usersAddUserController', {
                $scope: scope,
                usersAddUserService: mockedAddUserService
            });
        }));

        it('should call getCountryPhoneCodes method on init', function () {
            //when            
            spyOn(mockedAddUserService, 'getCountryPhoneCodes').and.callThrough();

            deferred.resolve();

            scope.$root.$digest();

            //then
            expect(mockedAddUserService.getCountryPhoneCodes).toHaveBeenCalled();
        });

    });
}());

运行测试后，错误消息为：

PhantomJS 1.9.8（Windows 7 0.0.0）usersAddUserControllerUnitTest应该在init FAILED上调用getCountryPhoneCodes方法
    Expected spy getCountryPhoneCodes to have been called.

我显然遗漏了一些东西，但我无法弄清楚它是什么。任何帮助将不胜感激。

Answer 1

在将模拟传递到实例化控制器之后，您正在监视模拟。

试试这个：

describe('usersAddUserControllerUnitTest', function () {
    var scope, deferred, objectUnderTest, mockedAddUserService, $controller;

    beforeEach(module('app'));

    beforeEach(inject(function ($rootScope, $q, _$controller_) {
        scope = $rootScope.$new();

        function emptyPromise() {
            deferred = $q.defer();
            return deferred.promise;
        }

        mockedAddUserService = {
            getCountryPhoneCodes: emptyPromise
        };

        $controller = _$controller_;
    }));

    function makeController() {    
        objectUnderTest = $controller('usersAddUserController', {
            $scope: scope,
            usersAddUserService: mockedAddUserService
        });
    }

    it('should call getCountryPhoneCodes method on init', function () {
        //when

        spyOn(mockedAddUserService, 'getCountryPhoneCodes').and.callThrough();
        makeController();

        deferred.resolve();

        scope.$root.$digest();

        //then
        expect(mockedAddUserService.getCountryPhoneCodes).toHaveBeenCalled();
    });

});

编辑感谢@juunas注意到我的解决方案中的错误

Answer 2

您可以像这样提供模拟：

mockedAddUserService = {
    getCountryPhoneCodes: emptyPromise
};


beforeEach(function () {
    module(function ($provide) {
        $provide.value('usersAddUserService', mockedAddUserService);
    });
});

编辑：

代码应该看起来（因为我无法测试），如下所示：

(function () {
    'use strict';

    describe('usersAddUserControllerUnitTest', function () {        
        beforeEach(module('app'));

        var emptyPromise = function() {
            var deferred = $q.defer();
            return deferred.promise;
        }

        var mockedAddUserService = {
            getCountryPhoneCodes: emptyPromise
        };

        beforeEach(function () {
            module(function ($provide) {
                $provide.value('usersAddUserService', mockedAddUserService);
            });
        });

        var scope;
        beforeEach(inject(function ($rootScope, $q, $controller) {
            scope = $rootScope.$new();
            $controller('usersAddUserController', {
                $scope: scope
            });
        }));

        it('should call getCountryPhoneCodes method on init', function () {
            spyOn(mockedAddUserService, 'getCountryPhoneCodes').and.callThrough();

            scope.$root.$digest();

            expect(mockedAddUserService.getCountryPhoneCodes).toHaveBeenCalled();
        });

    });
}());

茉莉花控制器测试，预计间谍被称为

2 个答案: