Question

在以下代码中，如果ng-selected值未变为True，那么为什么ng-init不会选择option value=3。如果ng-selected变为true，则应显示选择的值，否则为默认值，即选项3

右下拉显示未选择任何选项。

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

Answer 1

在ng-init中，您将issue设为'3'，而不是item.issue.id。

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue.id='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

Answer 2

我认为ng-init应该设置id

的值

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue.id='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

具有ng选定问题的Angularjs ng-init

2 个答案: