我有一个类似
的数组arr(0) = {jan,jan,feb,feb,feb,mar,mar,mar,apr,apr}
如何计算每个值的数量并删除重复值?
答案 0 :(得分:3)
这样的东西?
Dim grouping = arr.GroupBy(Function(x) x).Select(Function(g) New With {g.Key, Key .Count = g.Count()})
For Each g In grouping
Console.WriteLine(g.Key & ":" & g.Count)
Next
Dim distinctList = grouping.Select(Function(x) x.Key)
For Each item In distinctList
Console.WriteLine(item)
Next
答案 1 :(得分:1)
计算每个值的数量:
arr(0).Length
删除重复的元素:
Public Sub RemoveDuplications(Of T)(ByRef arr() As T)
Dim filteredList As List(Of T) = New List(Of T)
For Each element As T In arr
' If element is already added in the list, skip the elementi
If filteredList.Contains(element) Then Continue For
' Add element to the list
filteredList.Add(element)
Next
' Return filtered array
arr = filteredList.ToArray()
End Sub
用法:
RemoveDuplications(Of Integer)(a(0))
或`RemoveDuplications(Your_Array_Type)(Array_Variable)
答案 2 :(得分:1)
我建议yoo创建两个临时数组,一个int“到达”(def值为0),一个字符串为“arrs”(def值为“”),带有你的arr
'我伪代码
for int iStart = 0 to arr.count
dim findIT as integer
for findIT = 0 to arrs.count
if (arrs(findIT ) = "") then
arrs(findIT ) = arr(iStart)
arri(findIT ) = arri(findIT )+1
exit for
else if (arrs(findIT ) = arr(iStart)) then
arri(findIT ) = arri(findIT )+1
exit for
end if
next
next
for int iShow = 0 to arrs.count
if (Not(arrs(findIT ) = "")) then
'print arrs(findIT ) has arri(findIT ) occurrences
else
exit for
end if
next