Question

我在网站上看到了这个错误。

不推荐使用：mysql_query（）：不推荐使用mysql扩展名   将来删除：使用mysqli或PDO代替   第3行/home/u857740002/public_html/datafetch.php

不推荐使用：mysql_query（）：不推荐使用mysql扩展名   将来删除：使用mysqli或PDO代替   第23行/home/u857740002/public_html/datafetch.php

我正在使用此代码。

任何人都可以纠正这两行。

$siteSettings = mysql_query("select * from pu_settings where sid = '1' ");
$siteSoft = mysql_query("select * from pu_softwares where slug = '$slug' ");

Answer 1

MySQL_ *已被弃用，很快就会被PHP删除。使用MySQLi_ *。请参阅：AST

请改用：

$link = mysqli_connect([dbhost],[dbusername],[dbpass],[dbname]);

$siteSettings = mysqli_query($link,"select * from pu_settings where sid = '1' ");
$siteSoft = mysqli_query($link,"select * from pu_softwares where slug = '$slug' ");

Answer 2

mysql_*已弃用+已移除库，因此请使用mysqli_*或PDO： -

假设您的数据库连接对象为$conn

$siteSettings = mysqli_query($conn,"select * from pu_settings where sid = '1' ")or die(mysqli_error($conn));
$siteSoft = mysql_query($conn,"select * from pu_softwares where slug = '$slug' ")or die(mysqli_error($conn));

使用mysqli_*创建连接的代码是： -

$conn=mysqli_connect("hostname","username","password","databasename");

if (mysqli_connect_errno()){
 echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

Answer 3

在查询中使用mysqli_*代替mysql_*。

$con=mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$siteSettings = mysqli_query($con,"select * from pu_settings where sid = '1' ");
$siteSoft = mysqli_query($con,"select * from pu_softwares where slug = '$slug' ");

这个PHP代码出错

3 个答案: