Question

如何组合2个表按日期排序并将它们输出到列表中？这就是我现在所拥有的。

列表中的日期应为此格式2015-06-27 23:00

SELECT date, name, quantity, FROM downloads ORDER BY(`Date`) DESC
SELECT date, name, quantity, price, FROM sales ORDER BY(`Date`) DESC


$result_sales = $mysqli->query($sql_sales);

while($row = $result_sales->fetch_assoc()){
       $sale = rown["quantity"];
       $name = row["name"]; 
       $date_str = strtotime($row["date"]);
       $year = date('Y', $date_str);
       $month = date('n', $date_str) - 1;
       $day = date('j', $date_str);
       $hour = date('H', $date_str);
       $minute = date('i', $date_str);
       $ans_sales = " " . sprintf('%s, %s, %s, %s, %s',$year,$month,$day,$hour,minute) . " - ".  $name ." - " .  $sale . " - Sale Added";
       echo $ans_sales . ",\r\n";
}

Answer 1

删除,附近的FROM。

SELECT date, name, quantity, price, FROM sales ORDER BY(`Date`) DESC
                                  ^^

对于组合两个表使用UNION ALL

(SELECT date, name, quantity FROM downloads ORDER BY `Date` DESC)

UNION ALL

(SELECT date, name, quantity, price FROM sales ORDER BY `Date` DESC)


ORDER BY `Date` DESC

Answer 2

SELECT date, name, quantity, 0 as price FROM downloads
union all
SELECT date, name, quantity, price FROM sales
ORDER BY(`Date`) DESC

Answer 3

使用查询

创建一个mysql VIEW'view_all'

SELECT 
        date, 
        name, 
        quantity,
        null as price
    FROM downloads 

    UNION ALL

    SELECT 
        date, 
        name, 
        quantity, 
        price
    FROM sales

然后执行

SELECT * FROM'view_all'ORDER BY（date）DESC;

合并2个表并按日期字段对它们进行排序，并将结果作为列表输出

3 个答案: