Question

我正在尝试使用PHP创建一个表。

出于某种原因，我无法显示密钥。知道为什么吗？

这是表格。

这是我尝试过的代码：

String[] array = {"Henry", "Henry", "Henry", "Maxwell", "Maxwell"};

HashMap<String, Integer> duplicates = new HashMap<String, Integer>();

for (String s : array) {
    Integer i = duplicates.get(s);
    duplicates.put(s, i == null ? 1 : (i+1));
}

有什么想法吗？

Answer 1

试试这个

#include <stdio.h>

int main(void) 
{
   int Val_MAX = 0;

   printf("Enter the value of Val_MAX\n");
   scanf("%d", &Val_MAX);

   if(Val_MAX)
      printf("The value is %d",VALUE_MAX);

   return 0;
}

简要说明：

正如您在图像中所示，您需要定义预定义的标题，这些标题可以使用<table> <tr> <th>User #</th> <th>First Name</th> <th>Last Name</th> <th>Full Name</th> <th>Full Name in UpperCase</th> </tr> <?php $users = array( array('first_name' => 'Michael', 'last_name' => 'Choi'), array('first_name' => 'John', 'last_name' => 'Supsupin'), array('first_name' => 'Mark', 'last_name' => 'Guillen'), array('first_name' => 'KB', 'last_name' => 'Tonel') ); foreach ($users as $key => $user) { echo "<tr>"; echo "<td>" , $key + 1 , "</td>"; echo "<td>" . $user['first_name'] . "</td>"; echo "<td>" . $user['last_name'] . "</td>"; echo "<td>" . $user['first_name'] . " " . $user['last_name'] . "</td>"; echo "<td>" . strtoupper($user['first_name']) . " " . strtoupper($user['last_name']) . "</td>"; echo "<td></td>"; echo "</tr>"; } ?> </table>以及从<th></th>数组中获取的其余值来完成，这些数据可以放在循环中。< / p>

注意：在这里你需要使用单循环而不是嵌套循环，如例子所示

Answer 2

您应该使用<tr>和<td>。

      <table border="1">
           <?php

        $users = array( 
           array('first_name' => 'Michael', 'last_name' => 'Choi'),
           array('first_name' => 'John', 'last_name' => 'Supsupin'),
           array('first_name' => 'Mark', 'last_name' => 'Guillen'),
           array('first_name' => 'KB', 'last_name' => 'Tonel') 
        );

         $array_number = count($users)-1; 

                for($i=0; $i<=$array_number; $i++){
                 ?>
                 <tr> <td><?php echo $users[$i]['first_name']; ?></td><td><?php echo $users[$i]['last_name']; ?></td> </tr>
         <?php       } 

        ?>

        </table>

Answer 3

问题是你在数组上循环两次，一次是foreach，一次是for。但是你只需要一个循环。选择一个。

另外，养成在回显变量内容时始终使用htmlspecialchars的习惯。在这种情况下它不重要，但有时，你不知道变量在哪里！

另外，请参阅Amol的答案。

Answer 4

<table>    <?php

$users = array(     array('first_name' => 'Michael', 'last_name' => 'Choi'),    array('first_name' => 'John', 'last_name' => 'Supsupin'),  array('first_name' => 'Mark', 'last_name' => 'Guillen'),    array('first_name' => 'KB', 'last_name' => 'Tonel')  );

$i = 1;

     foreach($users as $key => $user) {
        echo "<tr>";
       echo "<td>" . $i . "</td>";
             echo "<td>" . $user['first_name'] . "</td>";
             echo "<td>" . $user['last_name'] . "</td>";
        echo "</tr>";  $i++;
        }


?>

</table>

希望有所帮助

Answer 5

<table> <tr> <th>User #</th> <th>First Name</th> <th>Last Name</th> <th>Full Name</th> <th>Full Name in UpperCase</th> </tr>

<?php $users = array( array('first_name' => 'Michael', 'last_name' => 'Choi'), array('first_name' => 'John', 'last_name' => 'Supsupin'), array('first_name' => 'Mark', 'last_name' => 'Guillen'), array('first_name' => 'KB', 'last_name' => 'Tonel') );

foreach ($users as $key => $user) {
    echo "<tr>";
    echo "<td>" , $key + 1 , "</td>";
    echo "<td>" . $user['first_name'] . "</td>";
    echo "<td>" . $user['last_name'] . "</td>";
    echo "<td>" . $user['first_name'] . " " . $user['last_name'] . "</td>";
    echo "<td>" . strtoupper($user['first_name']) . " " . strtoupper($user['last_name']) . "</td>";
    echo "<td></td>";
    echo "</tr>";   
}
?>

`

用PHP创建表

5 个答案: